All categories

2 years ago

11-1\2y=3+6x Solve for y

Mathematics

2 answers:

myrzilka [38]2 years ago

8 0

The answer is y=4/3.

romanna [79]2 years ago

5 0

Let's solve for y.

11−12y=3+6x

Step 1: Add -11 to both sides.

−1/2y+11+−11=6x+3+−11

−12y=6x−8

Step 2: Divide both sides by (-1)/2.

−1/2y−1/2=6x−8/-1/2

y=−12x+16

You might be interested in

Asap plz thankyouuuuuuuuuuuuuuuuuuuuuuuu

maria [59]

Number 5 is 135 because angle 3 is congruent to 7 and 7 is 135

5 0

2 years ago

If the equation y² - (K- 2y + 2k +1 = 0 with equal roots find the value of k

777dan777 [17]

Answer:

y² - (K- 2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

8 0

2 years ago

What is the parallel line and slope of a perpendicular like for 3x+5y=4

jonny [76]

Answer:

a line parallel has the same slope and different y-intercept, and the slope of the perpendicular line would be -3/5

Step-by-step explanation:

3x + 5y = 4

5y = -3x + 4

y = -3/5x + 4/5

8 0

2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Whats the answer & how do I solve it ?

Veseljchak [2.6K]

Answer:

Area of rectangle = 225/2 or 112.5

Step-by-step explanation:

Given,

Consider a rectangle ABCD.

Let AC be a diagonal of rectangle of length = 15

In triangle ABC.

Sin 45° =height/hypotenuse {SinФ = height / hypotenuse}

Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)

And height is AB

Therefore, sin 45° = AB/AC

or sin 45° = AB / 15

or 1/√2 = AB /15

AB = 15/√2

Similarly we can find Base (i.e BC) using cosine.

Cos 45° = Base/Hypotenuse

Cos 45° = BC / AC

or 1/√2 = BC/15

BC = 15/√2

Hence we got length of rectangle , AB= 15/√2

And width of rectangle , BC = 15/√2

Therefore, area of rectangle = Length × Width

Area of rectangle = 15/√2 × 15/√2 = 225/2

Hence, area of rectangle = 225/2 = 112.5

6 0

2 years ago