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mina [271]
3 years ago
13

Ahmed found the volume of a cone having both a height and a diameter of 6 centimeters. His work is shown below. Step 1 Find the

radius. radius = StartFraction 6 Over 2 EndFraction = 3 centimeters Step 2 Find the area of the base. Area of base = Pi (3) squared = 9 pi centimeters squared Step 3 Multiply the area of the base by the height. 9 pi times 6 = 54 centimeters cubed Step 4 Divide 54 by 3 to find the volume of the cone. Volume of the cone = StartFraction 54 Over 3 EndFraction = 18 centimeters cubed What was Ahmed’s first error? In Step 1, the radius should be found by multiplying the diameter by 2. In Step 2, the formula 2 pi r should be used to find the area of the circle. In Step 3, the resulting area should be in terms of pi. In Step 4, the units of the resulting volume should be Centimeters squared.
Mathematics
2 answers:
kaheart [24]3 years ago
8 0

Answer:

C- step 3, the resulting area should be in terms of pi

Step-by-step explanation:

I did the test on edge, I passed

nirvana33 [79]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Got A 100%

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Sum of three like fractions is 18/11. the first 2 fractions are 1/11 and 9/11. find the third fraction.
Mariulka [41]

Answer:

\frac{8}{11}

Step-by-step explanation:

Since the fractions are like, their denominators are 11, then

consider the values that sum to give 18 , that is

1 + 9 + ? = 18

10 + ? = 18 ( subtract 10 from both sides )

? = 8

Then the third fraction is \frac{8}{11}

5 0
2 years ago
Rachel and Hugo sorted 265 crayons each box had 10 crayons how many crayons are left?
ryzh [129]

Answer:

20

Step-by-step explanation:

6 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
Read 2 more answers
Goods are purchased for ₹1500. If one fifth of the goods sold at a profit of 5% and the remaining four-fifth of the goods at a p
Tpy6a [65]

Answer:

9%

Step-by-step explanation:

Cost of 1/5 good = 1500*1/5= 300

Profit= 5%

SP = (profit+100)/100*CP

SP= (5+100)/100*300

SP = 105/100*300

SP= 1.05*300= 315

Cost of 4/5 good = 1500*4/5= 1200

Profit= 10%

SP= (profit+100)/100*CP

SP= (10+100)/100*1200

SP = 110/100*1200

SP= 1.10*1200= 1320

Total SP = 315+1320= 1635

Net profit= 1635-1500= 135

Profit% = 135/1500*100%

Profit% = 0.09*100%

Profit% = 9%

6 0
3 years ago
Read 2 more answers
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Marta_Voda [28]

Answer:

Fido's decision is sensible because the cost of the car loan should be less this credit history improves

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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