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amm1812
3 years ago
8

A park is 5 miles east of Roxana's home. A library is 4 miles north of the park. How far is Roxana's home from the library? ​

Mathematics
1 answer:
Ber [7]3 years ago
8 0

Answer: 9 miles I think but I dont know where her house is exactly.

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Hello! Can someone please help? I would really appreciate it! Thx! :)
Vika [28.1K]

Answer:

55

Step-by-step explanation:

a line is 180° so you subtract 180 by 125 and you get 55

5 0
3 years ago
Read 2 more answers
Find the measure of ZDCF. C F mDF = 49 G E MEG = 127 Find the measure of angle DCF​
AleksandrR [38]

Answer:

Step-by-step explanation:

Comment

If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)

Givens

Arc EG = 127

Arc DF = 49

Solution

<DCF = 1/2(127 - 49)

<DCF = 1/2(78)

<DCF = 39

8 0
2 years ago
Kiera and Trina joined a gym. The gym offers two different payment plans. Kiera chose Plan 1 and pays $25 a month and no fee to
Lady_Fox [76]

Answer:

t1 = $25m

t2 = $(10m + 100)

Step-by-step explanation:

Here we want to write equations

Kiera chose plan 1

$25 monthly and no joining fee

So the amount after m months will be 25 * m

t1 = $25m

Trina chose plan 2

$10 a month and $100 joining fee

after m months , total payment will be

10(m) + 100 = $(10m + 100)

Thus t1 = $25m and t2 = $(10m + 100)

6 0
3 years ago
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
PLS HURRRRRRRYYYYY TYYY
Ede4ka [16]

Answer:

It's 15.70796. Won't go in-depth since time seems to be of the essence

Step-by-step explanation:

Won't go in-depth since time seems to be of the essence

8 0
3 years ago
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