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3 years ago

Round nine point four two to one decimal place

1 answer:

5 0

Well in order to round 9.42 to the closest whole number we must know that. anything below 5 we round down and 5 and up we round up

So 9.42 becomes 9

of if your wanting to round to the nearest tenth it would be 9.4 you drop the 2 because you rounded down since it was lower than 5.

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a ship sails 20km due north. It changes direction and then sails 15 due east. How far is it from its starting point?

Feliz [49]

It is 35km from its starting point

7 0

3 years ago

What is the missing reason in the proof?

uranmaximum [27]

subtraction property of equality

6 0

4 years ago

Read 2 more answers

Express the product of 2x2 + 7x - 10 and x + 5 standard form.

podryga [215]

Answer: 2x3 + 17x2 + 25x - 50

Step-by-step explanation: Just try to distribute it at every step as follows:

Step 1: Start with the following:

(a + b + c)(d + e)

Step 2: Distribute (d + e) to each of the term in the first parenthesis

a(d + e) + b(d + e) + c(d + e)

Step 3: Distribute d and e to each term:

(ad + ae) + (bd + be) + (cd + ce)

or ad + ae + bd + be + cd + ce without the parentheses.

Step 4: Finally, simplify.

Using the above you should be able to do the following

Step 1: (2x2 + 7x - 10)(x + 5)

Step 2: 2x2(x + 5) + 7x(x + 5) - 10(x + 5)

Step 3: 2x3 + 10x2 + 7x2 + 35x - 10x - 50

Step 4: 2x3 + 17x2 + 25x - 50

4 0

3 years ago

If 2 fair dice are tossed what is the probability that the sum of the number of dots on the top faces will be 7

Salsk061 [2.6K]

Answer:

⅙

Step-by-step explanation:

it could be 6 and 1, 5 and 2, 4 and 3, 3 and 4, 2 and 5 or 1 and 6.

It is 2 fair dice, so all together, the probability is 36.

6/36 can be simplified to ⅙

3 0

2 years ago

How is the sum expressed in sigma notation?<br><br> 11 + 17 + 23 + 29 + 35 + 41

Advocard [28]

Answer:

The given sums 11+17+23+29+35+41 can be written as in sigma notation is $\sum\limits_{i=1}^{6}5+6i$

Therefore 11+17+23+29+35+41= $\sum\limits_{i=1}^{6}5+6i$

Step-by-step explanation:

Given series is 11+17+23+29+35+41

To find the given sum expressed in sigma notation :

11+17+23+29+35+41 can be written as the given sums in sigma notation is $\sum\limits_{i=1}^{6}5+6i$

That is

11+17+23+29+35+41= $\sum\limits_{i=1}^{6}5+6i$

Now expand the sums and to verify that whether the summation is true or not :

$\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))$

$=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)$

$=11+17+23+29+35+41$

Therefore 11+17+23+29+35+41= $\sum\limits_{i=1}^{6}5+6i$

8 0

3 years ago