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3 years ago

A bell curve ____ A. Normal Distribution B. Negatively Skewed C. Positively Skewed

Mathematics

1 answer:

salantis [7]3 years ago

8 0

It should be A. Normal Distribution.

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You can make one square with four toothpicks. Show how you can make two squares with 10 toothpicks and five squares with 12 toot

dsp73

Answer:

by doing it the same way you did with the first one.

Step-by-step explanation:

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3 years ago

4^{5} times 4^{3} WHAT'S THE ANSWER

Alchen [17]

4^8 is the answer according to the law of indices

7 0

3 years ago

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If carol travels 4 miles and her car averages 28 miles per hour, how long will it take carol to complete the distance? Express t

Anna11 [10]

Answer: t= Distance/Speed = 4/28= 1/7

Step-by-step explanation:

Speed is 28miles /hr

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Time(t) = Distance /Speed

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3 years ago

34 ft/min = ft/h please show example I want to know how to do it

Masteriza [31]

You know that there are 60 minutes in one hour, so you multiply 34 x 60.

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3 years ago

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A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min

sesenic [268]

$A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})$
$\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$
$A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4$

We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C$
$A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}$

Given that $A(0)=30$ , we have

$30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02$

so the amount of salt in the tank at time $t$ is

$A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}$

3 0

3 years ago