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faltersainse [42]

3 years ago

12

Indicate the equation of the given line in standard form. The line with slope 9/7 and containing the midpoint of the segment who

se endpoints are (2, -3) and (-6, 5).

1 answer:

vfiekz [6]3 years ago

5 0

I got y = 9/7x - 3/7

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Which of the following expressions could be used to represent "the difference between -17 and -8"?

musickatia [10]

The last bc the + and - are different that means it will be subtracted.

7 0

3 years ago

If S is the midpoint of RT , RS=8x+11 and ST =14x-1 find x

garri49 [273]

Answer:

From the given, we establish this relationship:

RS + ST = RT

RS = ST since S is the midpoint of RT

Thus, let's use RS = ST to find x,

By substituting the given expressions:

RS = ST

8x + 11 = 14x - 1

12 = 6x

x = 12/6

thus,

x = 2

4 0

3 years ago

Cos(−θ)=√3/3, sinθ<0

Delicious77 [7]

Answer:

$\sin\theta=-\frac{\sqrt{6}}{3}$

Step-by-step explanation:

The given trigonometric equation is $\cos(-\theta)=\frac{\sqrt{3} }{3}$ .

We can either use the Pythagorean identity or the right angle triangle to solve for $\sin\theta$ .

According to the Pythagorean identity,

$\cos^2\theta+\sin^2\theta=1$

Recall that, the cosine function is an even function, therefore

$\cos(-\theta)=\cos(\theta)$

$\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}$ .

We substitute this value in to the above Pythagorean identity to get;

$(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1$

$\Rightarrow \frac{3}{9}+\sin^2\theta=1$

$\Rightarrow \sin^2\theta=1-\frac{3}{9}$

$\Rightarrow \sin^2\theta=\frac{6}{9}$

$\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}$

$\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}$

But we were given that,

$\sin\theta\:$ , so we choose the negative value.

$\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}$

The correct answer is B

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3 years ago

Simplify the following expression:<br><br> 7472

Rainbow [258]

Answer:

7^2

Step-by-step explanation:

i hope this helps :)

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3 years ago

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larisa86 [58]

Answer:

6

Step-by-step explanation:

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3 years ago

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