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Margarita [4]
3 years ago
14

Need help! ASAP! With algebra

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

2;4;3

Step-by-step explanation:

y=2x²+4x+3

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Lou eat 6/8 of a pizza. what fraction of the in simplest form, Is left over?
vagabundo [1.1K]
If he ate 6/8 of the pizza, that means 2/8 is left.
2/8 simplify it, by dividing it by 2 and your answer is...
IT'S 1/4
3 0
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Can some one help me with this will give brainliest
a_sh-v [17]
The first one would be C and the 2nd is A. 
7 0
3 years ago
What is the slope of the line that passes through the points (2,7) and (8,-5)
Nookie1986 [14]

Answer:

m = -12 / 6 = -2 / 1 = -2

So its -2

3 0
3 years ago
If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?
Keith_Richards [23]
\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}

so, the domain is all real numbers EXCEPT that one.
4 0
3 years ago
Prove the polynomial identity.
aleksandr82 [10.1K]

Explanation:

Since we have given that

(2x+1)^2-2(2x+1)

Now, we have to prove it as

(2x+1)(2x-1)

Now, start the iterations:

(2x+1)^2-2(2x+1)\\\\=4x^2+1+4x-4x-2\\\\=4x^2+1-2\\\\=4x^2-1\\\\=(2x)^2-1\\\\=(2x+1)(2x-1)

So, first blank will be filled with

4x^2+4x+1

Second blank will be filled with

4x^2-1

Hence proved.

7 0
3 years ago
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