Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
The values that make this statement falser are any in which a and b do not have the same sign.
For instance, if a was equal to 3 and b was equal to -3 than see the results.
|a+b|=
|3+-3|=
|0|= 0
Then see the next equation with the same selections
|a|+|b|
|3|+|-3|
3 + 3 = 6
And this would be true no matter which is the negative, as long as there is one negative and one positive.
Answer: 12.69 miles approx
Step-by-step explanation:
let x represent the number of miles traveled
1.75 + 0.65x = 10
0.65x = 8.25
x = 12.69 miles approx
I think It's 0.9% I'm not sure though or 1.03%
