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aniked [119]
3 years ago
8

How many solutions does this equation have? 3(n + 4) = 3n + 11

Mathematics
1 answer:
Basile [38]3 years ago
4 0

Answer:

No solution.

Step-by-step explanation:

3(n + 4) = 3n + 11

Distribute on the left side.

3n + 12 = 3n + 11

Subtract 3n from both sides.

12 = 11

Since 12 = 11 is a false statement, there are no solutions.

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The sum of three consecutive integers is 114. what are the three integers?
RSB [31]

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Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 114 and it asks us to find the integers.

3 consecutive integers can be represented as followed.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer</em>

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<em />

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÷3    ÷3   ← <em>divide both sides of the equation by 3</em>

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X + 1 ⇒ <em>second integer   = 38</em>

X + 2 ⇒ <em>third integer   = 39</em>

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<em>Therefore, our 3 consecutive integers are 37, 38, and 39.</em>

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How do you write 4 x 4 x 4 x 5 x 5 in index notation
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Step-by-step explanation:

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