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attashe74 [19]
3 years ago
10

Help me please I beg you

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0
Good Luck................................................................

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20 POINTS, and BRAINIEST
mel-nik [20]

Answer:

the answer is ..........

$51.20

4 0
3 years ago
Read 2 more answers
Whats the answer for this <br> 4b²+20b+25
WITCHER [35]
4b²+20b+25=0

Divide everything by 4 

b²+5b+ 6.25=0 

use the quadratic formula 
x= (-b+ or - √b²-4ac) /2a
x= (-5 + or - √5²-4*1*6.25) /2(1)
x= -5/2 so
in this case, b= -5/2

7 0
3 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
3 years ago
Find the lcm of 56 and 72​
Reptile [31]

Answer:

504

Step-by-step explanation:

4 0
3 years ago
To find the product of two digit number and a 1 digit number you can multiply the tens multiply the ones and find of each
kumpel [21]

Yes you can multiply 10 to find the numbers

4 0
3 years ago
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