First term(a)=2
D=8
Now
t13=a*12D
=2*12*8=192
Answer= 192
Answer:
7.1 weeks to 68.4 weeks
Step-by-step explanation:
Chebyshev's Theorem states that:
75% of the measures are within 2 standard deviations of the mean.
89% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 38.1
Standard deviation = 10.1
Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Between 3 standard deviations of the mean.
So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks
Answer:
True
Step-by-step explanation:
3x5=15
15+8=23
23=23
Common ratio, is r=6/3=12/6=2
Answer: common ratio 2
First term a₁ = 3
nth term aₙ = a₁rⁿ⁻¹ = 3 (2ⁿ⁻¹)
13th term = 3(2¹²) = 12288
Answer: 13th term is 12,288
A and B is not, because if you were to make the A bigger it'll be the same as B, so I think is C
