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maxonik [38]
4 years ago
14

What is the difference between a cannabinoid and a trichome?

Physics
1 answer:
Sedbober [7]4 years ago
3 0
<span>Trichome density and type and cannabinoid content of leaves and bracts were quantitated during organ ontogeny for three clones of Cannabis sativa L. Trichome initiation and development were found to occur throughout leaf and bract ontogeny. On leaves, bulbous glands were more abundant than capitate-sessile glands for all clones, although differences in density for each gland type were evident between clones. On pistillate bracts, capitate-sessile glands were more abundant than the bulbous form on all clones, and both types decreased in relative density during bract ontogeny for each clone. The capitate-stalked gland, present on bracts but absent from vegetative leaves, increased in density during bract ontogeny. The capitate-stalked gland appeared to be initiated later than bulbous or capitate-sessile glands during bract development and on one clone it was first found midway in bract ontogeny. Nonglandular trichomes decreased in density during organ ontogeny, but the densities differed between leaves and bracts and also between clones. Specific regulatory mechanisms appear to exist to control the development of each trichome type independently.</span>
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The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
BigorU [14]

1. Frequency: 7.06\cdot 10^{14} Hz

The frequency of a light wave is given by:

f=\frac{c}{\lambda}

where

c=3\cdot 10^{-8} m/s is the speed of light

\lambda is the wavelength of the wave

In this problem, we have light with wavelength

\lambda=425 nm=425\cdot 10^{-9} m

Substituting into the equation, we find the frequency:

f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2. Period: 1.42 \cdot 10^{-15}s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

The frequency of this light wave is 7.06\cdot 10^{14} Hz (found in the previous exercise), so the period is:

T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


4 0
3 years ago
Read 2 more answers
Brandon is flying to the Western United States. His plane manages to cover 700 miles in 2 hours.
Naddik [55]

thats cool for brandon

4 0
3 years ago
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What are two ways to change the state of a substance
Papessa [141]
By burning the substance, or by digesting it.
6 0
3 years ago
What is the instantaneous velocity of a freely falling object 12 s after it is released from a position of rest?
vova2212 [387]
U=0ms^-1
t=12s
a=-9.81ms^-1
v=?

from an equation,v=u+at

v=0+(-9.81)(12)
=-117.72ms^-1
7 0
4 years ago
Two airplanes leave an airport at the same time.The velocity of the first airplane is 700 m/h at a heading of 31.3 the velocity
MArishka [77]

Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity

v_{12} = v_1 - v_2

here

speed of first plane is 700 mi/h at 31.3 degree

v_1 = 700 cos31.3\hat i + 700 sin31.3\hat j

v_1 = 598.12\hat i + 363.7\hat j

speed of second plane is 570 mi/h at 134 degree

v_2 = 570 cos134 \hat i + 570 sin134 \hat j

v_2 = -396\hat i + 410\hat j

now the relative velocity is given as

v_{12} = (598.12 + 396)\hat i + (363.7 - 410)\hat j

v_{12} =994.12\hat i -46.3 \hat j

now the distance between them is given as

d = v* t

d = (994.12 \hat i - 46.3 \hat j)* 3

d = 2982.36\hat i - 138.9\hat j

so the magnitude of the distance is given as

d = \sqrt{2982.36^2 + 138.9^2}

d = 2985.6 miles

so the distance between them is 2985.6 miles

5 0
3 years ago
Read 2 more answers
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