All categories

3 years ago

Which statement describes the endothermic reaction by this graph?

Physics

2 answers:

alexgriva [62]3 years ago

8 0

Answer:

endothermic: heat taking in

exothermic: heat given out

lara [203]3 years ago

3 0

Answer:

I thin that the answer is d because the energy goes high and then it goes down a bit

Explanation:

You might be interested in

Gravity anything with mass as gravity we know the earth has gravity because you and I are standing on earth and not floating off

Paraphin [41]

Answer:

$F=mg$

Explanation:

Close to Earth's surface, the force of gravity that pulls an object towards the ground is

$F=mg$ (2)

where

m is the mass of the object

g is the acceleration due to gravity, which is $9.81 m/s^2$ close to Earth's surface

This is an approximation of the general formula of gravity valid only close to Earth's surface. The more general formula is

$F=G\frac{Mm}{r^2}$ (1)

where

G is the gravitational constant

M is the Earth's mass

m is the object's mass

r is the distance of the object from Earth's center

At the Earth's surface,

r = R (Earth's radius), and by calling the following factor

$g=\frac{GM}{R^2}$

we see that eq.(1) becomes eq.(2).

8 0

2 years ago

As beverages are produced what action will increase the solubility of co2 in them most?

Alla [95]

Answer: D. decreasing the temperature

Explanation:

8 0

3 years ago

Read 2 more answers

how do i write this to where it is true? in the blue is a statement and the attached piece is false so i have to make it true an

OlgaM077 [116]

Answer:

cross out the false piece in blue and write the true piece in red

4 0

3 years ago

Consider three planets. All have the same mass as Earth, but with different radii (from largest to smallest: Planet 1, 2, 3). Fo

LuckyWell [14K]

Answer:

option C

Explanation:

given,

mass of the three planet is same

radius of the planets are

R₁ > R₂ > R₃

expression of escape velocity

$v = \sqrt{\dfrac{2GM}{R}}$

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

from the above expression we can clearly conclude that the escape velocity is inversely proportional to the radius of the Planet.

radius of planet increases escape velocity decreases.

Hence planet 3 has the smallest radius so the escape velocity of the third planet will be maximum.

The correct answer is option C

3 0

3 years ago

xConsider the following reduction potentials: Cu2+ + 2e– Cu E° = 0.339 V Pb2+ + 2e– Pb E° = –0.130 V For a galvanic cell employi

slega [8]

Answer:

Approximately $\rm 90\; kJ$ .

Explanation:

Cathode is where reduction takes place and anode is where oxidation takes place. The potential of a electrochemical reaction ( $E^{\circ}(\text{cell})$ ) is equal to

$E^{\circ}(\text{cell}) = E^{\circ}(\text{cathode}) - E^{\circ}(\text{anode})$ .

There are two half-reactions in this question. $\rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu$ and $\rm Pb^{2+} + 2\,e^{-} \rightleftharpoons Pb$ . Either could be the cathode (while the other acts as the anode.) However, for the reaction to be spontaneous, the value of $E^{\circ}(\text{cell})$ should be positive.

In this case, $E^{\circ}(\text{cell})$ is positive only if $\rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu$ is the reaction takes place at the cathode. The net reaction would be

$\rm Cu^{2+} + Pb \to Cu + Pb^{2+}$ .

Its cell potential would be equal to $0.339 - (-0.130) = \rm 0.469\; V$ .

The maximum amount of electrical energy possible (under standard conditions) is equal to the free energy of this reaction:

$\Delta G^{\circ} = n \cdot F \cdot E^{\circ} (\text{cell})$ ,

where

$n$ is the number moles of electrons transferred for each mole of the reaction. In this case the value of $n$ is $2$ as in the half-reactions.
$F$ is Faraday's Constant (approximately $96485.33212\; \rm C \cdot mol^{-1}$ .)

$\begin{aligned}\Delta G^{\circ} &= n \cdot F \cdot E^{\circ} (\text{cell})\cr &= 2\times 96485.33212 \times (0.339 - (-0.130)) \cr &\approx 9.0 \times 10^{4} \; \rm J \cr &= 90\; \rm kJ\end{aligned}$ .

5 0

2 years ago