Answer:
1.3 rev/s
Explanation:
= Moment of inertia when arms and one leg of the skater is out = 3.5 kgm²
= Moment of inertia when arms and legs of the skater are in = 0.80 kgm²
= Angular speed of skater when arms and legs of the skater are in = 5.5 rev/s
= Angular speed of skater when arms and legs of the skater are out = ?
Using conservation of angular momentum
=
(0.80) (5.5) = (3.5)
= 1.3 rev/s
The potential energy of a 2-μc charge at that point in space is joules.
Given,
V=400v, q=2-μc=2*,
U(potential energy)=V*q=400*2*=
joules.
The energy that an item retains due to its position in relation to other objects, internal tensions, electric charge, or other reasons is known as potential energy in physics. The gravitational potential energy of an object is based on its mass and the distance from the centre of mass of another object. Other common types of potential energy include the elastic potential energy of an extended spring and the electric potential energy of an electric charge in an electric field. The joule, denoted by the sign J, is the SI's definition of an energy unit.
The vectors that are described as gradients of a particular scalar function known as potential can be used to represent these forces, also known as conservative forces, at any location in space.
At a certain point in space there is a potential of 400 v. what is the potential energy of a 2-μc charge at that point in space? group of answer choices'
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To solve this problem it is necessary to take into account the concepts of Intensity as a function of Power and the definition of magnetic field.
The intensity depending on the power is defined as
Where
P = Power
r = Radius
Replacing the values that we have,
The definition of intensity tells us that,
Where,
Magnetic field
Permeability constant
c = Speed velocity
Then replacing with our values we have,
Re-arrange to find the magnetic Field B_0
Therefore the amplitude of the magnetic field of this light is