Which pair of elements has the most similar properties?
1 answer:
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Answer:
The magnitude of the new electric field is <u>35820 N/C</u>.
Explanation:
Given:
Original magnitude of electric field (E₀) = 2388 N/C
Original voltage = 'V' (Assume)
Original separation between the plates = 'd' (Assume)
Now, new voltage is three times original voltage. So,
New distance is 1/5 the original distance. So,
Now, electric field between the parallel plates originally is given as:
Let us find the new electric field based on the above formula.
Now, . So,
Therefore, the magnitude of the new electric field is 35820 N/C.
Answer:
The magnitude of the induced Emf is
Explanation:
The width of the truck is given as 79inch but we need to convert to meter for consistency, then
The width= 79inch × 0.0254=2.0066 metres.
Now we can calculate the induced Emf using expresion below;
Then the
Where B= magnetic field component
L= width
V= velocity
=(40*10^-6) × (42) × (2.0066)
=0.003371V
Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V