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baherus [9]
3 years ago
8

Which pair of elements has the most similar properties?

Physics
1 answer:
Vanyuwa [196]3 years ago
7 0
The answer is B, because oxygen and sulfur are in the same group (group 6A)
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Please help on this one?
diamong [38]

Answer:

ITS C

Explanation:

7 0
3 years ago
When making maps of the large-scale universe, astronomers estimate distances to the vast majority of galaxies by using:
Vesnalui [34]

Answer:

<em>The comoving distance and the proper distance scale</em>

<em></em>

Explanation:

The comoving distance scale removes the effects of the expansion of the universe, which leaves us with a distance that does not change in time due to the expansion of space (since space is constantly expanding). The comoving distance and proper distance are defined to be equal at the present time; therefore, the ratio of proper distance to comoving distance now is 1. The scale factor is sometimes not equal to 1. The distance between masses in the universe may change due to other, local factors like the motion of a galaxy within a cluster.  Finally, we note that the expansion of the Universe results in the proper distance changing, but the comoving distance is unchanged by an expanding universe.

4 0
3 years ago
If the magnitude of the resultant force is to be 500n, directed along the positive y axis, determine the magnitude of force f an
scoundrel [369]
The answer is 0=45.2 degrees
5 0
3 years ago
What is the formula to find initial velocity?​
Inga [223]

Answer:

s = ut + 1/2at^2

Explanation:

s= distance

u= initial velocity

a= acceleration

7 0
3 years ago
A rescue pilot drops a survival kit while her plane is flying at an altitude of 1.5 km with a forward velocity of 100.0 m/s. If
tresset_1 [31]

1750 meters.  
First, determine how long it takes for the kit to hit the ground. Distance over constant acceleration is: 
d = 1/2 A T^2
 where
 d = distance
 A = acceleration
 T = time 
 Solving for T, gives
 d = 1/2 A T^2
 2d = A T^2
 2d/A = T^2
 sqrt(2d/A) = T 
 Substitute the known values and calculate.
 sqrt(2d/A) = T
 sqrt(2* 1500m / 9.8 m/s^2) = T
 sqrt(3000m / 9.8 m/s^2) = T
 sqrt(306.122449 s^2) = T
 17.49635531 s = T 
 Rounding to 4 significant figures gives 17.50 seconds. Since it will take
17.50 seconds for the kit to hit the ground, the kit needs to be dropped 17.50
seconds before the plane goes overhead. So just simply multiply by the velocity. 
17.50 s * 100 m/s = 1750 m
3 0
3 years ago
Read 2 more answers
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