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3 years ago

Can someone help me with one through seven I will mark you the brainly

Physics

2 answers:

pogonyaev3 years ago

7 0

1. F=ma

2. Force

3. Second law

4. a)first

b)second

C) third

5. Third

6. a) second

b) third

C) first

7. First

ki77a [65]3 years ago

3 0

Answer:

1. F = M x A

2. Force

3. 2nd Law: Force

4. a, b, c (in order)

5. 3rd Law: Action and Reaction

6. b, c, a (in order)

7. 1st Law: Inertia

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gtnhenbr [62]

Answer:

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Explanation:

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Current, I = 1.05 x 10⁴ A

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$B = \dfrac{\mu_0NI}{2R}$

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3 years ago

Kepler's laws and explanations

IgorC [24]

Answer:

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3 years ago

Need help on this, will mark brainliest if you answer.

Alecsey [184]

Answer:

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A cyclotron is to accelerate protons to an energy of 5.4 MeV. The superconduction electromagnet of the cyclotron produces a 2.9T

mart [117]

<h3>Answer;</h3>

Radius = 0.0818 m

Angular velocity = 2.775 × 10^7 rad/sec

<h3>Explanation;</h3>

The mass of proton m=1.6748 × 10^-27 kg;

Charge of electron e= 1.602 × 10^-19 C;

kinetic energy E= 2.7 MeV

= 2.7 × 10^6 × 1.602 × 10^-19 J;

= 4.32 × 10^-13 Joules

But; K.E =0.5m*v^2,

Hence v=√(2K.E/m)

Velocity = 2.27 × 10^7 m/s

Angular velocity, ω = v/r

Therefore; V = ωr

Hence; V = √(2K.E/m) = ωr

r= √(2E/m)/w = √E*√(2*m)/(eB)

= √E * √(2×1.6748×10^-27)/(1.602×10^-19 ×2.9)

but E = 4.32 × 10^-13 Joules

r = 0.0818 m

Angular speed

Angular velocity, ω = v/r , where r is the radius and v is the velocity

Therefore;

Angular velocity = 2.27 × 10^7 / 0.0818 m

= 2.775 × 10^7 rad /sec

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3 years ago