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3 years ago

How do I turn r - (4+p)=1/3r into a sentence?

Mathematics

1 answer:

xeze [42]3 years ago

6 0

The word form of this equation is <u>"r minus the sum of four and p is equal to one third of r."</u>

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WILL GIVE BRANLIEST!!! Pls help! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the

iren [92.7K]

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

$d=\sqrt{h^2+k^2}$

Distance of P from ( -3, 4 ) :

$d=\sqrt{(h+3)^2+(k-4)^2}$

Now , these distance are equal :

$h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2$

Solving above equation , we get :

$P=(\dfrac{16}{21},\dfrac{23}{7})$

Hence , this is the required solution.

6 0

3 years ago

What makes the sentence true 1\2=?/12

bagirrra123 [75]

It would be 1/2 = 6/12

6 0

4 years ago

Draw a model that shows 1.7

Ne4ueva [31]

This is how it would look like, hope that this is not too late to help you yet! Have a great day!

4 0

3 years ago

Please please give answer

rodikova [14]

Answer:

Then the total area is 116 cm^2 which agrees with answer D

Step-by-step explanation:

Notice we need to calculate the area of two rectangles (one larger at the bottom and a smaller one on top)

The Area of a rectangle is the product: base x height

In our case :

Area of Big rectangle = 12 cm x 7 cm = 84 cm^2

Area of smaller rectangle = 8 cm x 4 cm = 32 cm^2

Then the total area is: 84 cm^2 + 32 cm^2 = 116 cm^2

8 0

3 years ago

A purchaser of electric relays buys from two suppliers, A and B. Supplier A supplies two of every three relays used by the compa

inessss [21]

Answer:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.

Step-by-step explanation:

We can model this question with a binomial distribution random variable.

The sample size is n=60.

The probability that the relay come from supplier A is p=2/3 for any relay.

If we use a normal aproximation, we have the mean and standard deviation:

$\mu=np=60*(2/3)=40\\\\\sigma=\sqrt{npq}=\sqrt{60*(2/3)*(1/3)} =3.65$

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

$P(X\leq38)=P(X$

5 0

3 years ago