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kherson [118]
3 years ago
9

A rectangle and a triangle have the same area.

Mathematics
1 answer:
Ivanshal [37]3 years ago
7 0
Area of a rectangle is length times width. Area of a triangle is one-half base times height. Now just plug in everything we know and set the equations equal to each other.

(6)(8) = 0.5(8)(h)

Solve for height

48 = 4h

h = 12 m




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The combined height of one fir tree and one pine tree is 212121 meters. The height of 444 fir trees stacked on top of each other
inn [45]

Answer: The height of each fir tree is 9 meters, and the height of each pine tree is 12 meters.

Step-by-step explanation:

Let x= height of each fir tree, y = height of each pine tree.

As per given, we have

x+y = 21          (i)

4x=y+24        (ii)

From (ii),

4x-y=24            (iii)

Add (i) and (iii), we get

5x=45\\\\\Rightarrow\ x=\dfrac{45}{5}\\\\\Rightarrow\ x=9

Put value of x in (i), we get

9+y=21\Rightarrow y=12

Hence, the height of each fir tree is 9 meters, and the height of each pine tree is 12 meters.

3 0
2 years ago
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I need Help please ASAP!!!!<br>Please<br>Please<br>​
mafiozo [28]

Answer:

1.8?

Step-by-step explanation:

7 0
2 years ago
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Which digit is in the tenths place of 36
Volgvan
The digit would be 0 if its just 36
3 0
2 years ago
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Sebastian rides his bike 2,000 meters in 5 minutes. How many meters does he bike in 1 minute?
USPshnik [31]

Answer:400 meters

Step-by-step explanation:

2000/5=400

5 0
2 years ago
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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
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