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iragen [17]
3 years ago
11

Please help! will choose brainiest

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0
X=0.84....................
Lilit [14]3 years ago
7 0
X=11
.272727=27.272727/100
27.272727/9=approx3
100/9=approx 11
account for approximations 3/11
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What is cosA for this triangle?<br><br> 48/55<br><br> 55/73<br><br> 55/48<br><br> 48/73
mash [69]

For this case we must indicate the cosine of A, of the figure shown. By definition:

Cosine (A) = \frac {Cateto\ adjacent\ to\ the \ angle} {hypotenuse}

Substituting the values we have:

Cosine (A) = \frac {48} {73}

So, we have to:

Cosine (A) = \frac {48} {73}

Answer:

Option D

4 0
3 years ago
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the bottom of a vase is a square.each side measury y+11 units.the square has a perimeter of 55 units what is the value of y?
Norma-Jean [14]

Answer:

2.75

Step-by-step explanation:

55-11(4)=2.75

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3 years ago
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What is the decimal equivalent of each rational number a.7/20 b.-23/20 c.1/18 d.-60/22
Eva8 [605]

Answer:

a. 0.35

b. -1.15

c. 0.056

d. -2.727

4 0
2 years ago
What is a simpler form of the expression?<br><br> (2n^2 + 5n +3)(4n - 5)
coldgirl [10]

Answer:

8n³ + 10n² - 13n - 15

Step-by-step explanation:

Distribute the factors by multiplying each term in the first factor by each term in the second factor, that is

4n(2n² + 5n + 3) - 5(2n² + 5n + 3) ← distribute both parenthesis

= 8n³ + 20n² + 12n - 10n² - 25n - 15 ← collect like terms

= 8n³ + 10n² - 13n - 15

5 0
4 years ago
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The weights of a certain brand of candies are normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.
aleksandr82 [10.1K]

Answer:

The probability is 0.508 = 50.8%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.0525 g.

This means that \mu = 0.8544, \sigma = 0.0525

If 1 candy is randomly​ selected, find the probability that it weighs more than 0.8535 g.

This is 1 subtracted by the pvalue of Z when X = 0.8535. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.8535 - 0.8544}{0.0525}

Z = -0.02

Z = -0.02 has a pvalue of 0.492

1 - 0.492 = 0.508

The probability is 0.508 = 50.8%.

8 0
3 years ago
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