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Vedmedyk [2.9K]
3 years ago
12

= Initial Knowledge Check Rewrite the expression by factoring out (y+9). 3y^2 (y + 9) + 7(y+9)​

Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

3y {}^{2} (y + 9) + 7(y + 9) \\  = (y + 9)(3y { }^{2}  + 7)

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there are 12 teams in the jayhook hockey league each team plays every other team twice per season, once at home and once away. L
Gre4nikov [31]

Answer:

58

Step-by-step explanation:

As there are 12 teams in the league and each teams plays every other team twice per season. so, the total number of matches in the league will be 132.

let the matches won by home team = 'x'

given,

number of matches drawn = 34

matches won by the away team = x - 18

Now, according to the question,

⇒ total matches = matches drawn + matches won by home team + matches won by away team

⇒ 132 = 34 + x + x -18

⇒ x = 58

5 0
3 years ago
The function h represents the height of an object t seconds after it is launched into the air. The function is
nasty-shy [4]

Step-by-step explanation:

h(t) = -5t² + 20t + 18

this is a parabola (the curve an object follows when thrown up into the air and then falling back down).

and as such it will most likely have 2 solutions (one for when going up, and one for when falling back down again).

33 = -5t² + 20t + 18

15 = -5t² + 20t

-3 = t² - 4t

t² - 4t + 3 = 0

the solution of such a quadratic equation is

t = (-b ±sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -4

c = 3

t = (4 ±sqrt(16 - 4×1×3))/(2×1) = (4 ±sqrt(16-12))/2 =

= (4 ±sqrt(4))/2 = (4 ± 2)/2

t1 = (4+2)/2 = 6/2 = 3

t2 = (4-2)/2 = 2/2 = 1

the object reaches the height of 33 m first after 1 second (while going up), and then again after 3 seconds (while falling down again).

7 0
3 years ago
In abc above,what is the length of ad​
Nezavi [6.7K]

Answer:

B

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = \frac{\sqrt{3} }{2}, thus

sin60° = \frac{opposite}{hypotenuse} = \frac{BD}{BC} = \frac{BD}{12} = \frac{\sqrt{3} }{2} ( cross- multiply )

2BD = 12\sqrt{3} ( divide both sides by 2 )

BD = 6\sqrt{3}

-----------------------------------------------------------

Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = \frac{1}{\sqrt{3} } , thus

tan30° = \frac{opposite}{adjacent} = \frac{AD}{BD} = \frac{AD}{6\sqrt{3} } = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} AD = 6\sqrt{3} ( divide both sides by \sqrt{3} )

AD = 6 → B

4 0
3 years ago
If a ball is thrown upward at 29.4 meters per second from the top of a building that is 80 meters high, the height of the ball c
RoseWind [281]

Answer:

<h2>124.1m</h2>

Step-by-step explanation:

29.4 per sec > Building 80m

Height = S = 4.9t^2 + 29.4t + 80

Solve for t:

t = 1.24 (approximately)

If t needed coordinates / solve using the quadratic formula:

t = (1.24 , -7.24)

<h3>The ball's maximum height is 124.1 meters.</h3>
7 0
3 years ago
Shea has a annual salary of $29640. He works 40 hours a week, 52 weeks a year. How much does shea earn per hour?
pickupchik [31]
40*52=2080 (hours per year)
$29640/2080h=$14.25h


Shea earns $14.25 per hour
7 0
4 years ago
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