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babymother [125]

3 years ago

7

Evaluate ∫ x cos 3x dx. A. 1/3 x sin 3x + 1/9 cos 3x + C B. 1/3 x sin 3x - 1/3 sin 3x + C C. 1/2 x2 + 1/18 sin2 3x + C D. 1/6 x2

sin 3x + C

1 answer:

balandron [24]3 years ago

4 0

I = ∫ cos (3x) dx
Let u = 3 x
du = 3 dx
du/3 = dx
I = (1/3) ∫ cos u du
I = (1/3) sin u + C
<span> I = (1/3 sin (3x) + C

Hope that helps!!!!
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