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babymother [125]
3 years ago
7

Evaluate ∫ x cos 3x dx. A. 1/3 x sin 3x + 1/9 cos 3x + C B. 1/3 x sin 3x - 1/3 sin 3x + C C. 1/2 x2 + 1/18 sin2 3x + C D. 1/6 x2

sin 3x + C
Mathematics
1 answer:
balandron [24]3 years ago
4 0
I = ∫ cos (3x) dx
Let u = 3 x
du = 3 dx
du/3 = dx
I = (1/3) ∫ cos u du
I = (1/3) sin u + C
<span> I = (1/3 sin (3x) + C 



Hope that helps!!!!
</span>
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What's (2x) ^3 in expanded notation form?
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3 years ago
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JulsSmile [24]

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a) First bring all the fractions to a common denominator (I'm going to use 8th's). 5/8 is already simplified, 1/2=4/8, and 3/4=6/8. Then, simply add the numerators and leave the denominator:  \frac{5+4+6}{8} =\frac{15}{8}

Since this can not be simplified any further, your final answer is 15/8.

b) Start by bringing all the fractions to a common denominator (for this problem, we'll use 18th's). 2/3=12/18, 1/6=3/18, and 5/9=10/18. Then just add all the numerators and leave the denominator the same: \frac{12+3+10}{18} = \frac{25}{18}

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