I am trying to get the intersection of 8-16-24-32 and16-32-48
1 answer:
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Answer:
Area of the regular dodecagon inscribed in a circle will be 27 square units.
Step-by-step explanation:
A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.
Since angle formed at the center by a polygon =
Therefore, angle at the center of a dodecagon = = 30°
Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units
Now area of a small triangle =
where a and b are the sides of the triangle and θ is the angle between them.
Now area of the small triangle =
=
Area of dodecagon = 12×area of the small triangle
= 12×
= 27 unit²
Therefore, area of the regular octagon is 27 square unit.
