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zalisa [80]
3 years ago
10

I am trying to get the intersection of 8-16-24-32 and16-32-48

Mathematics
1 answer:
kakasveta [241]3 years ago
4 0
{8, 16, 24, 32}int.{16, 32, 48}={16, 32}
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d1i1m1o1n [39]

Answer:

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Step-by-step explanation:

6 0
3 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

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4 0
3 years ago
Can someone please help me answer this??
rewona [7]
<h3>Answer:  x = (y-2)^2 + 5</h3>

In other words, y-2 goes in the first box and 5 goes in the second box.

=================================================

Work Shown:

y^2 - 4y - x + 9 = 0

y^2 - 4y + 9  = x

x = y^2 - 4y + 9

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x = (y^2-4y+4) + 5

x = (y-2)^2 + 5  .... apply the perfect square factoring rule

So we'll have y-2 go in the first box and 5 goes in the second box

note: One version of the perfect square factoring rule says (a-b)^2 = a^2-2ab+b^2.

4 0
3 years ago
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Valentin [98]
1+200000-1+200000
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3 years ago
Find ‘x’ in:- <br> x:6 :: 5 : 11
melomori [17]

Answer:

<h3>x:6 :: 5 : 11</h3>

x = 6*5/11=30/11

7 0
2 years ago
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