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algol13
3 years ago
9

6 sweets cost 24p altogether how much do 5 sweets cost

Mathematics
1 answer:
iragen [17]3 years ago
4 0
24 divided by 6 equals 4. Each sweet is worth 4p. If you multiply 5 by 4 you get 20, so the answer is 5 sweets cost 20p.
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The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 i
fenix001 [56]

Answer:

Null hypothesis:\mu \geq 250        

Alternative hypothesis:\mu < 250  

p_v =P(t_{15}    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.      

Step-by-step explanation:

1) Data given and notation        

\bar X=510 represent the mean for the sample    

s=50 represent the standard deviation for the sample  

n=16 sample size        

\mu_o =530 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.      

t would represent the statistic (variable of interest)        

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.        

We need to conduct a hypothesis in order to determine if the claim thet the handle on average is 530 bags per hour:      

Null hypothesis:\mu \geq 530        

Alternative hypothesis:\mu < 530        

We don't know the population deviation and the sample size is lees than 30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:        

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)        

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic        

We can replace in formula (1) the info given like this:        

t=\frac{510-530}{\frac{50}{\sqrt{16}}}=-1.60        

4) Calculate the critical value

We need to begin calculating the degrees of freedom

df=n-1=16-1=15

The critical value for this case would be :

P(t_{15}

The value of a that satisfy this on the normal standard distribution is a=-1.75 and would be the critical value on this case zc=-1.75

5) Calculate the P-value        

Since is a one-side upper test the p value would be:        

p_v =P(t_{15}    

6) Conclusion        

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.      

8 0
2 years ago
I need help with numbers 7-9 please
jolli1 [7]

Answer:

C

5(10)+10=60

-2(-5)+7=17

Step-by-step explanation:


7 0
3 years ago
How much is f(10) if f=x^2-2
dangina [55]

To find this value, simply substitute the number 10 in for x in your equation:

f(x) = x^2 - 2

f(10) = 10^2 - 2 = \boxed{98}

The answer is 98.

8 0
2 years ago
Long before iPhones that hold thousands of songs and play
Flauer [41]

Answer:

Do you mean an MP3 player?

Step-by-step explanation:

4 0
2 years ago
pls help!? with all 4 Questions I would rlly appreciate your help thx to plp who help me I will improve on my math and be way be
aliina [53]
7.6=w/12
w=7.6(12)
w=91.2

x/2=20
x=20(2)
x=40

8.3x=41
x=41(8.3)
x=340.3

54=r/3
r=54(3)
r=162








6 0
3 years ago
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