All categories

3 years ago

6 sweets cost 24p altogether how much do 5 sweets cost

1 answer:

4 0

24 divided by 6 equals 4. Each sweet is worth 4p. If you multiply 5 by 4 you get 20, so the answer is 5 sweets cost 20p.

You might be interested in

Please click on the file and answer ASAP.

Annette [7]

Answer: Part a) 375 pounds, Part b) 8 words

Step-by-step explanation:

<u />

Since n represents the number of words there are, we can plug in 20 for n into the equation to get:

C = 15*20 + 75 pounds

C = 300 + 75 pounds

C = 375 pounds

Since C represents the cost of the advert, we can plug in 195 for C into the equation to get:

195 = 15n + 75

Subtract 75 from both sides:

120 = 15n

Divide both sides by 15:

n = 8 words

6 0

2 years ago

HELP ASAP TIMED!!!!!!!!!!!!!!!

jenyasd209 [6]

Step-by-step explanation:

1 ans 35/37

2 ans 0.95

3 ans 12/37

4 ans 0.32

3 0

2 years ago

A 3.4 metre ladder is leaning against a wall. The bottom of the ladder is 1.5m from the wall. Determine the angle formed between

xxTIMURxx [149]

Answer:

80 degree angle

Step-by-step explanation:

8 0

3 years ago

Find the height of a square pyramid that has a volume of 75 cubic feet and a base length of 5 feet.

Rudiy27

Answer:

9 ft

Step-by-step explanation:

Let's begin with the formula for the volume of a square pyramid. If s is the base length, then the area of the base is s^2. The volume of the pyramid is then V = (1/3)(base area)(height). We know the volume and the base length (s), and want to find the height. Solving V = (1/3)(base area)(height)

for height, we get:

3V = (base area)(height), or

---------------- = height

base area

Substituting 75 ft^3 for V and (5 ft)^2 for base area, we get:

3(75 ft^3) 9 ft

height = ------------------ = ----------------- = 9 ft

25 ft^2 1

3 0

3 years ago

Claim: The standard deviation of pulse rates of adult males is less than 11 bpm. For a random sample of 132 adult males, the pu

seraphim [82]

Answer:

$\chi^2 =\frac{132-1}{121} 114.49 =123.952$

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=132$ represent the sample size

$\alpha$ represent the confidence level

$s^2 =10.7^2 =114.49$ represent the sample variance obtained

$\sigma^2_0 =11^2=121$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 121$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{132-1}{121} 114.49 =123.952$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 131. And since is a right tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(123.952,131,TRUE)"

5 0

3 years ago