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Vikki [24]
3 years ago
7

A triangular prism has the same number of face true/false

Mathematics
1 answer:
KIM [24]3 years ago
3 0

Answer:

Its false

Step-by-step explanation:

Because it has 2 triangular bases and 3 rectangular bases. And the base is also a face.

Hope this answers the question.

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Consider the strategic games described below. In each case, state how you would classify the game according to the six dimension
katovenus [111]

Answer:

game show The Price is Right, four contestants are asked to guess the price of a television set. Play starts with the leftmost player, and each player's guess must be different from the guess of the previous players. The person who comes closest to the real price, without going over it, wins the television set.

c.) Six thousand players each pasy $10,000 to enter

8 0
3 years ago
Which equation has the same solution as x2 + 16x – 11 = 4?
strojnjashka [21]

Answer:

x^2 + 16x - 15 = 0.

Step-by-step explanation:

x^2 + 16x – 11 = 4    Subtract 4 from both sides:

x^2 + 16x - 15 = 0  is one equation with  the same roots.

Also any equation which is a multiple of the above will have the same roots. For example if we multiply by 3:

3x^2 + 48x - 45 = 0.

5 0
2 years ago
Jon and Lexi are playing a marble game. According to their rules, 4 points are awarded for each red marble collected and 7 point
lesantik [10]
For a red marble you have 4 points and a blue you have 7, therefore  the R(number of red marble) and B( blue marbles)
 the answer is gonna be :{4r+7b}
Hope this help

5 0
3 years ago
Read 2 more answers
In estimating the mean score on a fitness exam, we use an original sample of size and a bootstrap distribution containing bootst
zmey [24]

Answer:

Option A is correct.

The confidence interval becomes

66 to 74.

Step-by-step explanation:

Complete Correct Question

In estimating the mean score on a fitness exam, we use an original sample of size n = 30 and a bootstrap distribution containing 5000 bootstrap samples to obtain a 95% confidence interval of 67 to 73. A change in this process is described below. If all else stays the same, which of the following confidence intervals (A, B, or C) is the most likely result after the change: Using an original sample of size n=16?A. 66 to 74

B. 67 to 73

C. 67.5 to 72.

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

To calculate the Sample Mean, we will use the confidence imterval obtained for the first sample size of 30 was 67 to 73.

Let the mean be x and the margin of error = y.

Lower limit of the confidence interval = x - y = 67

Upper limit of the confidence interval = x + y = 73

Solving simultaneously,

Sample mean = 70

Margin of error = 3

Then, since the sample size was initially 30, the critical value was obtained from the z-tables.

95% critical value = z = 1.960

Margin of error = (critical value) × (standard error)

3 = 1.960 × (standard error)

Standard error = 1.5306

Standard error of the mean = σₓ = (σ/√n) = 1.5306

σ = standard deviation of the sample = ?

n = sample size = 30

1.5306 = (σ/√30)

σ = 1.5306 × √30 = 8.3835

Note that using the central limit theorem, we can assume that sample mean for a sample size of 30 people will be approximately equal to the same value, digital value, that is Adam score of 70.

Sample mean for sample size 16, = 70

Sample standard deviation = 8.3835

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

Critical value = 1.960

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8.3835

n = sample size = 16

σₓ = (8.3835/√16) = 2.096

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 70 ± (1.960 × 2.096)

CI = 70 ± 4.10

95% CI = (65.9, 74.1)

95% Confidence interval = (66, 74)

Hope this Helps!!!

3 0
3 years ago
Jodie spent 25% less buying her English reading books thank Claudia. .Gianna spent 9% less than Claudia. Gianna spent more than
Vikki [24]

Answer:

21.3%

Step-by-step explanation:

Given that:

Money spent by Jodie for buying English reading books = 25% lesser than that of Claudia

and

Money spent by Gianna is 9% lesser than that of Claudia.

To find:

By what percent, Gianna spent more than Jodie ?

Solution:

Let the money spent by Claudia on her English books = 100

Now, as per question statement:

Money spent by Jodie = 100 - \frac{9}{100}\times 100 = 75

Money spent by Gianna = 100 - \frac{25}{100}\times 100 = 91

Now, to find the answer:

\dfrac{\text{Difference between money spent by Gianna and Jodie}}{\text{Money spent by Jodie}}\times 100

\Rightarrow \dfrac{91-75}{75}\times 100\\\Rightarrow \dfrac{16}{75}\times 100\\\Rightarrow \bold{21.3\%}

Therefore, Gianna spent <em>21.3% </em>more than the amount that was spent by Jodie.

4 0
3 years ago
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