You draw a polygon on the graph
Solve it by substitution. First let's rewrite the first equation (3x+4y=16) so we have y = something, then we'll substitue that in to the other equation.
3x+4y=16
4y=-3x+16
y=-3/4x+4
Now we can substitute this into the other equation.
Answer: D. y = 3x − 1
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
From the graph,
y2 = 2
y1 = - 1
x2 = 1
x1 = 0
Slope,m = (2 - - 1)/(1 - 0) = 3/1 = 3
To determine the intercept, we would substitute x = 1, y = 2 and m= 3 into y = mx + c
y = mx + c. It becomes
2 = 3 × 1 + c = 3 + c
c = 2 - 3 = - 1
The equation becomes
y = 3x - 1
Is it x times 2 times y times 2? is that what it is asking or is it meaning squared
