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nekit [7.7K]
3 years ago
8

Can you help me on this question 6(r-8)=8r-36

Mathematics
1 answer:
erastova [34]3 years ago
8 0

Answer:

r = -6

Step-by-step explanation:

6(r - 8) = 8r - 36

distribute 6 into r - 8

6r - 48 = 8r - 36

add 36 to both sides

6r - 12 = 8r

subtract 6r from both sides

-12 = 2r

divide by 2 on both sides

-6 = r

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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
2 years ago
Find the dicontinuities of the function.
elena-s [515]

Answer:

Step-by-step explanation:

I'm assuming you meant to type in

f(x)=\frac{x^2+12x+27}{x^2+4x+3} because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to

f(x)=\frac{(x+3)(x+9)}{(x+1)(x+3)} and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.

The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!

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Answer:

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Step-by-step explanation:

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Answer:

First Option v+w = u

Step-by-step explanation:

To graphically add two vectors a and b using the -tail and tip-method, you must draw the tail of b at the tip of the vector a. Then you must draw a line that goes from the tail of a to the tip of b. This line represents the sum of a + b.

In this problem, notice that the tail of the vector w is on the tip of the vector v. The line that joins the tail of v with the tip of w is u.

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I believe it is B. I could be wrong but I am hoping that you get it right
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