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lilavasa [31]
2 years ago
8

Write a real world situation that can be represented by the equation 2(n+20)=110.

Mathematics
1 answer:
adell [148]2 years ago
6 0
Simplifying
2(n + 20) = 110

Reorder the terms:
2(20 + n) = 110
(20 * 2 + n * 2) = 110
(40 + 2n) = 110

Solving
40 + 2n = 110

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 2n = 110 + -40

Combine like terms: 40 + -40 = 0
0 + 2n = 110 + -40
2n = 110 + -40

Combine like terms: 110 + -40 = 70
2n = 70

Divide each side by '2'.
n = 35

Simplifying
n = 35
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It took Trina 1 hour and 30 minutes to shovel the snow from her neighbor’s driveway. During that time she burned 630 calories. H
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The first step to solve this problem is to convert 1h 30min into just minutes. since there are 60 minutes in 1 hour you take 60 and add it ot the 30 extra minutes to get a total of 90.

Now, this question is asking you to find how many calories <u>per</u> minute she burns. When you are asked to find ___ per___ all you have to do is divide the first number by the second one. In this case you will divide calories by minutes.

630/90=<u>7</u>

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Simplify.<br> (w^2 + 3w)-(w^2+5w-4<br><br> 8w-4<br> 2w^2 +8w-4<br> -2w+4<br> -2w
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-2w + 4

Step-by-step explanation:

Remove parenthesis because they make life semi-confusing but remember to distribute the negative: w^2 + 3w -w^2 - 5w + 4

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The Social Justice Club is going to rent a mammoth barbeque to cook the hot dogs for the hot dog sale After contacting three ren
zimovet [89]

Answer:

(A)Cost of Rental A, C= 15x

Cost of Rental B, C=5x+50

Cost of Rental C, C=9x+20

(B)

i. Rental C   ii. Rental A     iii. Rental B

Step-by-step explanation:

<u>Part 1</u>

Let x be the number of hours of the barbeque use by the club.

Rental A: $15/h

Cost of Rental A, C= 15hx

Rental B: $5/h + 50

Cost of Rental B, C=5x+50

Rental C: $9/h + 20

Cost of Rental C, C=9x+20

<u>Part 2</u>

The graph of the three models is attached below

<u>Part 3(11.05-4.30)</u>

If the barbecue's usage hour is from 11.05 to 4.30 when the football match ends.

Number of Hours between 11.05am and 4.30pm=4 hours 25 Minutes = 4.42 Hours

Cost of Rental A, C= 15x=15(4.42)=$66.30

Cost of Rental B, C=5x+50 =5(4.42)+50=$72.10

Cost of Rental C, C=9x+20=9(4.42)+20=$59.78

Rental C should be chosen as it offers the lowest cost.

<u>Part 4 (11.05-12.30)</u>

Number of Hours = 12.30 -11.05 =1 hour 25 Minutes = 1.42 Hours

  • Cost of Rental A, C= 15x=15(1.42)=$21.30 Cost of Rental B, C=5x+50 =5(4.42)+50=$57.10 Cost of Rental C, C=9x+20=9(4.42)+20=$32.78

Rental A should be chosen since it offers the lowest cost.

<u>Part 5</u>

If the barbecue is returned the next day, say after 24 hours

  • Cost of Rental A, C= 15x=15(24)=$360 Cost of Rental B, C=5x+50 =5(24)+50=$170 Cost of Rental C, C=9x+20=9(24)+20=$236

Rental B should be chosen as it offers the lowest cost.

6 0
3 years ago
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