The following cose will be used to copy assignment operator for CarCounter
<u>Explanation:</u>
Complete Program:
#include <iostream>
using namespace std;
class CarCounter
{
public:
CarCounter();
CarCounter& operator=(const CarCounter& objToCopy);
void SetCarCount(const int setVal)
{
carCount = setVal;
}
int GetCarCount() const
{
return carCount;
}
private:
int carCount;
};
CarCounter::CarCounter()
{
carCount = 0;
return;
}
// FIXME write copy assignment operator
/* Your solution goes here */
CarCounter& CarCounter::operator=(const CarCounter& objToCopy)
{
if(this != &objToCopy)
carCount = objToCopy.carCount;
return *this;
}
int main()
{
CarCounter frontParkingLot;
CarCounter backParkingLot;
frontParkingLot.SetCarCount(12);
backParkingLot = frontParkingLot;
cout << "Cars counted: " << backParkingLot.GetCarCount();
cout << endl << endl;
system("pause");
return 0;
}
A programming language is not used to talk from human to human. It is used to talk from a human to a computer. Computers are very dumb compared to us, so they need to be taught or spoken to in simple terms. Asking them something complex is far beyond their understanding, as they cannot learn anything beyond what has already been taught to them. Using print: “Hello, World” is the way to tell them to do stuff way less complex than when we say ‘write the words Hello, World on the screen’. A programming language is also not very easy to create. Talking to a computer in a dumb way reduces the process to make a new language for the computer to understand.
Answer:
Explanation:
Algorithm:
a. In each day, you will have to loop through the hotels that come to the hotel after you stayed last night.
b. If a hotel 'h' is found at more than 'd' distance away from last stayed hotel, then the hotel previous of 'h' is chosen to wait for that night. This is the greedy step, and you stay in this hotel.
c. The process for steps a and b is then repeated until we've reached the last hotel xn.
Running time:
Notice that the worst case occurs if each hotel is at a distance of successive multiples of 'd'. The best move is to estimate the distance to each hotel twice the whole computation in the scenario.
Thus, the total running time that could occur in the worst case is O(2n) = O(n). This is said to be linear time.
What game ? I’m not sure what ur trying to ask
