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nikitadnepr [17]
3 years ago
10

Number between 17/4 and V20

Mathematics
1 answer:
Daniel [21]3 years ago
3 0

Answer:

4.485

Step-by-step explanation:

 [divide 17 by 4]

  [  ]

Now, Midpoint of  4.25 and 4.472 =

Number between 4.25 and 4.472 =4.485

Or number between  and  is 4.485.

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Which expression is equivalent to (3x)?<br> А 3х3<br> в 6х3<br> C9x3<br> D27х3
sergey [27]

Answer:

A-3x3 bc the parentheses are multiplying

7 0
3 years ago
Read 2 more answers
What is one of the solutions to the following system of equations?
Amanda [17]

Answer:

(8,-1)

Step-by-step explanation:

Given :   x^{2} +y^{2} =65

               x+y=7

To Find: solution of given system of equations.

Solution:

Equation a :   x^{2} +y^{2} =65

Equation b :  x+y=7

Substitute the value of y from equation b in equation a

y from equation b : y = 7-x

Now substitute value of y in equation a

Thus equation a becomes:

 x^{2} +(7-x)^{2} =65

x^{2} +49+x^{2}-14x =65

2x^{2} -14x =65-49

x^{2} -7x -8=0

x^{2} -8x+x -8=0

x(x-8)+1(x-8)=0

(x+1)(x-8)=0

⇒ x= -1 and x = 8

Now substitute values of x  in equation b to obtains values of y

⇒ x+y=7

for x = -1

⇒ -1+y=7

⇒ y=7+1

⇒ y=8

Thus (x,y)=(-1,8)

For x =8

⇒ 8+y=7

⇒ y=7-8

⇒ y=-1

Thus (x,y)=(8,-1)

Hence Option A is the correct solution .


6 0
3 years ago
Read 2 more answers
Someone Help Me Pleaseee
Vedmedyk [2.9K]

Answer:

-3

Step-by-step explanation:

-1 -2 = -3

6 0
2 years ago
A farmer sells 7.8 kilograms of pears and apples at the farmer's market. 3/4 of this weight is pears, and the rest is apples. Ho
tangare [24]

Answer:

He sold 1.95 kilograms of apples.

Step-by-step explanation:

First we find out what 3/4 of 7.8 is.

3/4 of 7.8 = 5.85

Next we subtract 7.8 by 5.85

7.8 - 5.85 = 1.95

So, the answer is 1.95

Hope this helps! :)

4 0
2 years ago
Read 2 more answers
If ε = {whole numbers less than 50 but greater than 20} and X = {perfect squares}, Y = {factors of 12}, Z = {prime numbers}; fin
Zigmanuir [339]

Answer:

A. X∪Y = {25, 36, 49}

B. X∩Y = ∅ i.e empty set

C. X' = {21, 22, 23, 24, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}

D. X′∩Y∩Z = ∅

Step-by-step explanation:

We'll begin by determining the universal set (ε), set X, set Y and set Z.

This can be obtained as follow:

ε = {whole numbers less than 50 but greater than 20}

ε = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49}

X = {perfect squares}

X = {25, 36, 49}

Y = {factors of 12}

Y = ∅ i.e empty

Z = {prime numbers}

Z = {23, 29, 31, 37, 41, 43, 47}

A. Determination of X∪Y

X = {25, 36, 49}

Y = ∅

X∪Y =?

X∪Y => combination of elements in set X and Y without repeating any element in both X and Y.

X∪Y = {25, 36, 49}

B. Determination of X∩Y

X = {25, 36, 49}

Y = ∅

X∩Y =?

X∩Y => elements common to both set X and Y

X∩Y = ∅ i.e empty

C. Determination of X′

ε = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49}

X = {25, 36, 49}

X' =?

X' => elements in the universal set but not found in set X.

X' = {21, 22, 23, 24, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}

D. Determination of X′∩Y∩Z

X' = {21, 22, 23, 24, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}

Y = ∅

Z = {23, 29, 31, 37, 41, 43, 47}

X′∩Y∩Z =?

X′∩Y∩Z => elements common to set X', Y and Z

X′∩Y∩Z = ∅

4 0
2 years ago
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