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maksim [4K]
3 years ago
6

Is there a answer to this

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

mean=71

Step-by-step explanation:

Mean x¯¯¯x¯

71

Median x˜x~

72

Mode

64, 83, 79, 38, 81, 90, 59, 93, 70, 73, 71, 51

Range

55

Minimum

38

Maximum

93

Count n

12

Sum

852

Quartiles

Quartiles:

Q1 --> 61.5

Q2 --> 72

Q3 --> 82

Interquartile

Range IQR

20.5

Outliers

none

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83 divided by 2 and then subtract 7

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3 years ago
A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What
kifflom [539]

Answer:

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Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

<u>Solution</u>:

Let width  = x\ cm

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Height = x+3+4=x+7\ cm

<u>As we know:</u>

<u />Volume\ of\ box=length\times width\times height

308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\  Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\  x^{2} +14x+77=0\\ \\ \\

As width can never be in negative, x= 4\ cm

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4 0
3 years ago
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GarryVolchara [31]

Answer:

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Step-by-step explanation:

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Hope this helps you

8 0
3 years ago
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