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Olegator [25]
3 years ago
13

Please Please Help me

Mathematics
1 answer:
MrRa [10]3 years ago
3 0
It's C. The congruence statement tells you what parts of rhe polygon are congruent to each other, so basically which will have the same measure. In the statement, you can tell that PS is congruent to JL because theyre in the same "positions", just on opposite sides of the equal sign.
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Proving the Single Opposite Side Pair Theorem
omeli [17]

9514 1404 393

Explanation:

1. AD ≅ BC, AD ║ BC . . . . given

2. ∠DAC ≅ ∠BCA . . . . alternate interior angles theorem

3. AC ≅AC . . . . reflexive property

4. ΔDAC ≅ ΔBCA . . . . SAS postulate

5. AB ≅ CD, ∠BAC ≅ ∠DCA . . . . CPCTC

6. AB ║ CD . . . . converse of alternate interior angles theorem

7. ABCD is a parallelogram . . . . definition of a parallelogram (has 2 pairs of parallel & congruent sides)

_____

We don't know what your tiles/choices are for statements or reasons. We have shown the triangles are congruent, so their corresponding parts (sides/angles) are congruent. That lets us claim opposite sides are congruent and  parallel. YMMV

7 0
3 years ago
Simplify the expression sqrt21*(sqrt3+sqrt14)
arlik [135]

√21*(√3+√14)=

=√(21*3)+ √(21*14)

=√(7*3²)+ √(3*7²*2)

=3√7+7√6

7 0
3 years ago
Read 2 more answers
-0.005680 is how much greate r than<br> 0.004359
blondinia [14]

Answer: -0.010039

Step-by-step explanation:

-0.005680-0.004359=-0.010039

5 0
3 years ago
The graph of g(x) is transformed from its parent function, f(x). Apply concepts involved in determining the key features of a ra
Alik [6]

We are given the function:

g(x) = \frac{1}{x-6}

Domain:

The domain is the set of all possible x-values which will make the function "work", and will output real y-values.

In case of fractions, we must not have the denominator as zero , otherwise the function will become undefined.

So equating denominating equal to zero to find restriction.

x-6=0

x=6

So at x=6 , the function becomes undefined.

So domain is all real numbers except x=6.

Range:

For a fraction, we find domain of inverse function and that gives the range.

g(x) = \frac{1}{x-6}

replacing g(x) by y

y = \frac{1}{x-6}

switching y by x and x by y

x = \frac{1}{y-6}

solving for y,

y=\frac{1}{x} +6

Now here we find domain of this function.

Again for a fraction denominator cannot be zero

So range is :

g(x) >0 and g(x) <0

4 0
4 years ago
Read 2 more answers
It’s worth 13 points thank you!<br> :)
Gwar [14]

Answer: the answer is the 3rd bubble:)

Step-by-step explanation:

5 0
3 years ago
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