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Darya [45]
3 years ago
15

If 6x + 4 = 11x - 21, what is the value of x?

Mathematics
2 answers:
lianna [129]3 years ago
8 0
X=5

Explanation: 6x + 4 = 11x - 21
1). Subtract 4 from both sides and you will get 6x = 11x -25.
2). Subtract 11x from both sides and you should get -5x = -25.
3). Divide the -5 with -25 to get x alone and you should get X=5!

Check your work:
6(5) + 4 = 34 & 11(5) - 21 = 34
34=34.
WITCHER [35]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

11x - 6x = 4 + 21

5x = 25 (÷5)

x = 5

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The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
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Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

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length of two known sides, a and b = 21 m and 40 m respectively

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a + b + c = P

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c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

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            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

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