Question

In triangle MPN, angle P is a right angle. If cos N= 3/5 which of the following statements is true

Answer 1

Answer: Sin N = $\frac{4}{5}$

Step-by-step explanation:

Since we have given that

In triangle MPN, ∠P=90°

$\cos N=\frac{3}{5}$

As we know the formula for "Trigonometric Ratios":

$\cos N=\frac{Base}{Hypotenuse}=\frac{3}{5}$

By Pythagorus theorem , we get

$H^2=B^2+P^2\\\\5^2=3^2+P^2\\\\25=9+P^2\\\\25-9=P^2\\\\16=P^2\\\\P=\sqrt{16}\\\\P=4\ units$

So, we get,

$\sin N=\frac{Perpendicular}{Hypotenuse}=\frac{4}{5}$

Hence, Sin N = $\frac{4}{5}$