Answer:

Step-by-step explanation:
Given





Required
Probability of selecting a yellow then orange rock
From the question, we understand that the probability is that of without replacement.
Since the yellow, is first picked.
We need to determine the probability of picking a yellow rock, first.



The rock has reduced by 1;
Next is to determine the probability of picking an orange rock



The required probability is calculated as thus:




Answer:
< n < 
<u>Step-by-step explanation:</u>
| 3n - 2 | - 2 < 1
<u> +2 </u> <u>+2 </u>
| 3n - 2 | < 3
3n - 2 < 3 and 3n - 2 > -3
<u> +2 </u> <u>+2 </u> <u> +2 </u> <u> +2 </u>
3n < 5 and 3n > -1
n <
and n > 
< n < 
Interval Notation: 

Graph:
o--------------------o 
Answer:
A square
Step-by-step explanation:
<span>Answer:
Standard Form:
3.441
<span>Expanded forms can be written
like a sentence or stacked for
readability as they are here.</span>
Expanded Numbers Form:
<span><span> 3 </span><span>+ 0.4</span><span>+ 0.04</span><span>+ 0.001</span></span>
Expanded Factors Form:
<span><span> 3 ×1 </span><span>+4 × 0.1</span><span>+4 × 0.01</span><span>+1 × 0.001</span></span>
Expanded Exponential Form:
<span><span>3 × 100</span><span>+<span>4 × 10-1</span></span><span>+<span>4 × 10-2</span></span><span>+<span>1 × 10-3</span></span></span>
Word Form:
three and
four hundred forty-one thousandths
</span>
Answer:
the answer is C: m<CDB=63