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rjkz [21]
3 years ago
12

Hey! i’ll give brainliest please help.

Mathematics
1 answer:
iVinArrow [24]3 years ago
8 0

Answer:

It should be "adaptation and reconciliation".

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Find the area of 6,4,15 help please
ra1l [238]

Answer:

Ps. don't  show your link next time becuase if you look up sequin you get TEXAS. answer is 360

Step-by-step explanation:

multiply one at a time

4 0
3 years ago
It is 76°f at the 6000-foot level of a mountain, and 49°f at the 12,000-foot level of the mountain. write a linear equation to f
valina [46]

Answer:

t(x) = 103 -0.0045x

Step-by-step explanation:

We are given the following in the question:

Let the equation:

t(x) = a + bx

be the linear equation that represent temperature at an elevation x.

Temperature at 6000-foot level = 76 f

76 = a + 6000b

Temperature at 12000-foot level = 49 f

49 = a + 12000b

Solving the two equation, we get,

76-49 = -6000b\\27=-6000b\\\\b = \dfrac{-27}{6000}\\\\b = -0.0045\\76 = a + (-0.0045)6000\\76 = a -27\\a = 76 + 27\\a  =103

Thus, we can write the linear equation as:

t(x) = 103 -0.0045x

5 0
3 years ago
Find the value of x.
Mamont248 [21]
Honestly no idea... sorry
5 0
3 years ago
Help please The question is in the photo
Sergio039 [100]
I believe the answer to your question is 23
5 0
3 years ago
Read 2 more answers
if j is 21 inches, k is 12 inches, and angle M measures 62 degrees, then find m using the Law is Cosines. round your answer to t
AURORKA [14]

Answer:

18.7

Step-by-step explanation:

The Law of Cosines is c^2=a^2+b^2-2ab cos(C), where c is the unknown side length of a triangle, a and b are the remaining two side lengths, and C is the angle opposite to side c. To answer this question just plug in the known values:

m^2=21^2+12^2-2(21)(12) cos(62)

Simplify:

m^2=441+144-504 cos(62)

m^2=585-504 cos(62)

m=\sqrt{585-504cos(62)}

m≈18.665...

When rounded to the nearest tenth, m=18.7

6 0
3 years ago
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