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Arturiano [62]
3 years ago
5

In order to request the records of a prior case for review and possible reconsideration, the Supreme Court of the United States

issues which of the selections listed below to the lower courts?
Select one:

A. a summary judgement

B. an appeal

C. a writ of certiorari

D. a court order

​
Physics
2 answers:
malfutka [58]3 years ago
6 0

Answer: c

a writ of certiorari

11Alexandr11 [23.1K]3 years ago
4 0
C. A writ of certiorari
You might be interested in
The right eye and right lung are __________.
PilotLPTM [1.2K]

The correct answer is A) Ipsilateral

Explanation:

The term ipsilateral is commonly used to describe objects or structures that are on the same side of a body or structure. This term is correct to describe the right eye and the right lung because these two organs are on the same side of the body (the right side). This can also be used to describe other organs such as the left humerus and the left hand or the right ear and the right feet because these pairs are also on the same side. According to this, the correct answer is A.

3 0
3 years ago
A 850-kg sports car accelerates from rest to 95 km/h in 6.8 s .
swat32

From the calculations, the power expended is 43650 W.

<h3>What is the power expended?</h3>

Now we can find the acceleration from;

v = u + at

u = 0 m/s

v =  95 km/h or 26.4 m/s

t =  6.8 s

a = ?

Now

v = at

a = v/t

a = 26.4 m/s/ 6.8 s

a = 3.88 m/s^2

Force = ma = 850-kg * 3.88 m/s^2 = 3298 N

The distance covered is obtained from;

v^2 = u^2 + 2as

v^2 = 2as

s = v^2/2a

s = (26.4)^2/2 * 3.88

s = 696.96/7.76

s = 90 m

Now;

Work = Fs

Work =  3298 N * 90 m = 296820 J

Power =  296820 J/ 6.8 s

= 43650 W

Learn more about power expended:brainly.com/question/11579192

#SPJ1

5 0
2 years ago
What is the unit of self inductance?
stira [4]

Answer:

The correct answer to that question is HENRY

6 0
3 years ago
4. An airplane maintains a constant acceleration of 4.0 m/s2 [E] as it speeds up from 16 m/s [E] to 28 m/s [E].
ki77a [65]

Answer:

gyvtu jyut

Explanation:

6 0
3 years ago
Suppose that a comet that was seen in 550 A.D. by Chinese astronomers was spotted again in year 1941. Assume the time between ob
pickupchik [31]

To solve the problem it is necessary to apply the concepts related to Kepler's third law as well as the calculation of distances in orbits with eccentricities.

Kepler's third law tells us that

T^2 = \frac{4\pi^2}{GM}a^3

Where

T= Period

G= Gravitational constant

M = Mass of the sun

a= The semimajor axis of the comet's orbit

The period in years would be given by

T= 1941-550\\T= 1391y(\frac{31536000s}{1y})\\T=4.3866*10^{10}s

PART A) Replacing the values to find a, we have

a^3= \frac{T^2 GM}{4\pi^2}

a^3 = \frac{(4.3866*10^{10})^2(6.67*10^{-11})(1.989*10^{30})}{4\pi^2}

a^3 = 6.46632*10^{39}

a = 1.86303*10^{13}m

Therefore the semimajor axis is 1.86303*10^{13}m

PART B) If the semi-major axis a and the eccentricity e of an orbit are known, then the periapsis and apoapsis distances can be calculated by

R = a(1-e)

R = 1.86303*10^{13}(1-0.997)

R= 5.58*10^{10}m

7 0
3 years ago
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