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babunello [35]
3 years ago
14

Se puede apelar la circunstancias para justificar una decisión que afecta a otras personas

Physics
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

No

Explanation:

tratar de justificar nuestras propias decisiones es algo totalmente innecesario, ya que todos tenemos derecho a tomar decisiones que en ocasiones pueden afectar indirectamente a otras personas y no hay nada de malo en ello.

Por otro lado, si está tomando una acción o tomando una decisión únicamente con la intención de afectar a otras personas, su acción no tiene justificación alguna.

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In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.​
mina [271]

Answer:

CPD = 80

PCD = 44

Explanation:

Given

AB || CD

BAD = 56

CPA = 100

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

CPA + CPD = 180 --- angle on a straight theorem

Substitute 100 for CPA

100 + CPD = 180

Subtract 100 from both sides

100-100 + CPD = 180-100

CPD = 80

Next, we calculate PCD

We have that:

DAB= ADC = 56  --alternate angle

In triangle PCD

PCD + CPD + PDC = 180 --- angles in a triangle

Where

PDC = ADC = 56

So, we have:

PCD +80 + 56 = 180

PCD +136 = 180

Subtract 136 from both sides

PCD = 180 - 136

PCD = 44

6 0
3 years ago
Please help ASAP will mark brainliest How do we find the amount of uncertainty we should expect in our measurement of the period
kicyunya [14]

Answer:

The relative uncertainty gives the uncertainty as a percentage of the original value. Work this out with: Relative uncertainty = (absolute uncertainty ÷ best estimate) × 100%. So in the example above: Relative uncertainty = (0.2 cm ÷ 3.4 cm) × 100% = 5.9%. The value can therefore be quoted as 3.4 cm ± 5.9%.

Explanation:

hope it helps :)

4 0
3 years ago
Using Rayleigh's criterion, what is the smallest separation between two pointlike objects that a person could clearly resolve at
atroni [7]

 Answer:

y = 52.44 10⁻⁶  m

Explanation:

It is Rayleigh's principle that two points are resolved if the maximum of the diffraction pattern of one matches the minimum the diffraction pattern of the other

Based on this principle we must find the angle of the first minimum of the diffraction expression

         a sin θ= m λ

The first minimum occurs for m = 1

       sin θ =  λ  / a

Now let's use trigonometry the object is a distance L = 0.205 m

        tan θ = y / L

Since the angles are very small, let's approximate

        tan θ = sin θ/cos θ = sin  θ

        sin θ = y / L

We substitute in the diffraction equation

         y / L =  λ  / a

         y =  λ  L / a

Let's calculate

        y = 550 10⁻⁹ 0.205 / 2.15 10⁻³

        y = 52.44 10⁻⁶ m

7 0
3 years ago
Which term best describes a severe weather event characterized by heavy snowfall, strong winds, and reduced visibility?
Margaret [11]

Answer:

OC. blizzard

Explanation:

In the United States, the National Weather Service defines a blizzard as a severe snow storm characterized by strong winds causing blowing snow that results in low visibilities. ... A severe blizzard has winds over 72 km/h (45 mph), near zero visibility, and temperatures of −12 °C (10 °F) or lower.

4 0
3 years ago
A marble runs off the edge of a table that is 1.5 m high and the marble lands 0.50 m from the base of the table. a. How much tim
Free_Kalibri [48]

Answer:

t = 0.55[sg]; v = 0.9[m/s]

Explanation:

In order to solve this problem we must establish the initial conditions with which we can work.

y = initial elevation = - 1.5 [m]

x = landing distance = 0.5 [m]

We set "y" with a negative value, as this height is below the table level.

in the following equation (vy)o is equal to zero because there is no velocity in the y component.

therefore:

y = (v_{y})_{o}*t - \frac{1}{2} *g*t^{2}\\   where:\\(v_{y})_{o}=0[m/s]\\t = time [sg]\\g = gravity = 9.81[\frac{m}{s^{2}}]\\ -1.5 = 0*t -4.905*t^{2} \\t = \sqrt{\frac{1.5}{4.905} } \\t=0.55[s]

Now we can find the initial velocity, It is important to note that the initial velocity has velocity components only in the x-axis.

(v_{x} )_{o} = \frac{x}{t} \\(v_{x} )_{o} = \frac{0.5}{0.55} \\(v_{x} )_{o} =0.9[m/s]

3 0
3 years ago
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