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yuradex [85]
3 years ago
7

How much work is done lifting a 5 kg ball from a height of 2 m to a height of 6 m? (Use 10 m/s2 for the acceleration of gravity.

)
A) 100 J B) 200 J C) 300 J D) 400 J
Physics
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

B) 200 [J]

Explanation:

In order to solve this problem we must remember the definition of work which tells us that it is equal to the product of force by a distance, in this case, the force is the weight of the ball. The distance traveled is 4 [m] since 6-2 = 4[m]

F = m*g

where:

m = mass = 5 [kg]

g = gravity acceleration = 10 [m/s^2]

F = 5*10 = 50 [N]

w = F*d

where:

F = force = 50 [N]

d = 4 [m]

w = 50*4 = 200 [J]

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Equation of motion description is v=20+2t.How big is the initial speed,acceleration?
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the initial velocity is 20 m/s   and  the acceleration is 2 m/s²

Explanation:

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From first kinematic equation;

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If we compare  (v = u + at)   to     (v = 20 + 2t)

then, u = 20    and  

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Answer:

Check the first and the third choices:

<u><em /></u>

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Explanation:

Rewrite the table for better understanding:

Temperature of gas (K)     Volume of gas (L)

     298                                     4.55

     315                                      4.81

     325                                     4.96

     335                                        ?

Calculate the ratios temperature to volume with 3 significant figures:

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