How would the expression x3 - 64 be rewritten using difference of cubes? A. (x + 4)(x2 - 4x - 16) B. (x - 4)(x2 + 4x + 16) C. (x + 4)(x2 - 4x + 16) D. (x - 4)(x2 + 16x + 4)
2 answers:
Answer:
B. (x - 4)(x2 + 4x + 16)
Step-by-step explanation:
Difference of cubes can be rewritten as:
a^3 – b^3 = (a – b)(a^2 + ab + b^2)
So in this case, x^3 - 64 = x^3 - (4)^3 where a = x and b = 4
= (x-4)(x^2 + 4x + 4^2)
= (x-4)(x^2 + 4x + 16)
The answer is B.
Answer:
B. (x - 4)(x2 + 4x + 16)
Step-by-step explanation:
a3 – b3 = (a – b)(a2 + ab + b2)
substitute a=x n b=4 (cuz 64=4x4x4)
x3 - 64 = (x-4)(x2+4x+4x4)
= (x - 4)(x2 + 4x + 16)
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