Answer:
the answer is 64 im 100% sure
Answer:
The range of values for x is; 5 < x < 29
Step-by-step explanation:
The given parameters are;
= 15
= 18
=
Given
=
by reflexive property
∠BCA = 2·x - 10
∠DCA = 48°
Since 15 < 18, given the common sides of the tringle ΔABC and triangle ΔADC, angle ∡(2·x - 10)° < 48°
Therefore;
2x - 10 < 48
2·x < 48 + 10
∴ x < 29
Also, given that 2·x - 10 is real, 0 < 2·x - 10
10 < 2·x
10/2 < x
5 < x
Therefore, an acceptable range is 5 < x < 29
Perimeter of a square = 4s
Required perimeter =
triangle B. because congruent is supposed to be the same shape same size but triangle b is same shape but a different size
Answer:
A
Step-by-step explanation:
We need to find a equation that is where the domain is all real numbers and the range is all real numbers greater than -3
- A square root function cannot equal to all real numbers because we cant take the square root of a negative number. so B and C are already wrong.
- A cubic function range is all real numbers. so y can be greater than -3 but it would also include. values lesser than -3. so D is Wrong.
A is right, the domain of a absolute value function is all real numbers. The range of a absolute value is all numbers greater than or equal to zero but if we subtract 3, it changes into all real numbers greater than or equal to -3