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3 years ago

Hello!

Mathematics

1 answer:

Zina [86]3 years ago

7 0

Answer:

1. Less Steeper

2. Reflected over the x axis

3. Steeper

Step-by-step explanation:

You might be interested in

Suppose you are given that a=b+2 and b+2=5. What can you prove by using these statements and the Transitive Property?

Nataliya [291]

You can prove that a=5, b=3, 5=3+2 and a=b+2.

4 0

2 years ago

PLEASE HELP ASAP.

alexandr1967 [171]

Answer:

$Y' = (-2, 4\frac{2}{3})$

Step-by-step explanation:

Given

$Y = (-3,7)$

$Scale\ Factor = (\frac{2}{3}x,\frac{2}{3}y)$

Required

Determine Y'

Y' can be solved by multiplying the scale factor by Y

i.e.

$Y' = Scale\ Factor * Y$

For, the x coordinates.

$Y' = \frac{2}{3}x$

Where

$x = -3$

$Y' = \frac{2}{3} * -3$

$Y' = \frac{-6}{3}$

$Y = -2$

For the y coordinates:

$Y' = \frac{2}{3}y$

Where

$y = 7$

$Y' = \frac{2}{3} * 7$

$Y' = \frac{14}{3}$

$Y' = 4\frac{2}{3}$

Hence:

$Y' = (-2, 4\frac{2}{3})$

3 0

2 years ago

A silo is a composite of a cylindrical tower with a cone for a roof. Find the volume of the silo if the

xxMikexx [17]

Answer:

5127079.21 cubic feet

Step-by-step explanation:

The silo is in the shape of a cylinder and a cone.

The volume of the silo will be the sum of the volumes of the cylinder and the cone.

Therefore, its volume is:

$V = \pi r^2h + \frac{1}{3} \pi rH$

where r = radius of cylinder and cone

h = height of cylinder

H = height of cone

The radius of the base is 120 feet, the height of the roof (cone) is 25 feet. The height of the entire silo is 130 feet. This means that the height of the cylinder is:

130 - 25 = 105 feet

Therefore, the volume of the silo is:

$V = (\pi * 120^2 * 105) + (\frac{1}{3} * 120^2 * 25)\\\\V = 4750088.09 + 376991.12\\\\V = 5127079.21 ft^3$

The volume of the silo is 5127079.21 cubic feet.

3 0

2 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ <em>cross multiply</em>

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

2 years ago

Which values of a and b make the equation true

bixtya [17]

Love your profile pic

5 0

2 years ago