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LekaFEV [45]
3 years ago
11

Please find the square roots of the following complex number.

Mathematics
1 answer:
Nana76 [90]3 years ago
6 0

Hey there,

First, find the square root of the given equation.

\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})

Best of Luck!

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An elephant can run of a mile in 36 seconds. At this rate, which expression can be used to determine how fast an elephant runs i
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<u>Answer:</u>

The expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

<u>Solution:</u>

Given that,

Distance covered by an elephant in 36 seconds is equal to 1 mile

Therefore, <em>distance covered by the elephant in 1 second</em> is  \frac{1}{36} mile

Therefore, <em>distance covered by the elephant in 60 seconds</em> (60 seconds = 1 minute) is

\frac{1}{36} \times 60=\frac{5}{3} \text { miles }

Therefore, <em>distance covered by the elephant in 60 minute</em> (60 minute = 1 hour) is

\frac{5}{3} \times 60=100 \text { miles per hour }

Hence the expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour

7 0
3 years ago
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Answer:

D)90

Step-by-step explanation:

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5 0
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Read 2 more answers
Select the expression that is equal to (-2x +9) – (3x – 4).
Anna [14]

Answer:

C

Step-by-step explanation:

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3 0
3 years ago
Which data set is the most clustered around its mean?
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A because it is a pattern 4 6 4 8 and that is why it is a
8 0
4 years ago
Several students from boxerville middle stood in a circle, evenly spaced, to play a game. If the 6th student was directly across
myrzilka [38]

Answer:

There were 14 students in the circle

Step-by-step explanation:

* Lets explain how to solve the problem

- The students stood in a circle

∴ The line joining each two opposite students is the diameter

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∴ The 6th student is opposite to the 13th student

- Lets count how many students between 6th student and

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∵ 7th , 8th , 9th , 10th , 11th , 12th students between the 6th

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∴ There are 6 students between them

∵ There are 6 students between 6th and 13th

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∵ There are 2 students in 6th and 13th

∴ The number of the students = 6 + 6 + 2 = 14

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8 0
4 years ago
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