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LekaFEV [45]
3 years ago
11

Please find the square roots of the following complex number.

Mathematics
1 answer:
Nana76 [90]3 years ago
6 0

Hey there,

First, find the square root of the given equation.

\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})

Best of Luck!

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6x - 5 = 5x + 3<br> If you get it right you get brainest
matrenka [14]

Answer:

x = 8

Step-by-step explanation:

6x - 5 = 5x + 3

6x - 5x = 3 + 5 (combining like-terms)

x = 8

Hope this helps!

4 0
2 years ago
PLEASE HELP AND BE CORRECT
Sergio [31]

(b⁷/4⁵)⁻³

= (4⁵/b⁷)³

= 4¹⁵/b²¹

Therefore answer is option b

Must click thanks and mark brainliest

3 0
3 years ago
You deposit $500 into a savings account that earns 3.2% annual interest. How much is in the savings account after 10 years?
Brilliant_brown [7]
A = P(1 +r/n)^nt
P = 500
r = 3.2% = 0.032
n = 1
t = 10

A = 500(1 + 0.032)^10
A = $685.12
7 0
2 years ago
Find the area of each figure. Round to the nearest tenth if necessary.
natita [175]

Answer:

Solution given:

1.

diameter(d)=6mm

base(b)=8mm

height (h)=5mm

Area of figure=area of parallelogram +area of semi circle

  • base*height+½π(d/2)²
  • 8*5+½*π×(6/2)²
  • 40+14.14
  • 54.4mm²
  • <u>Area</u><u> </u><u>:</u><u>5</u><u>4</u><u>.</u><u>1</u><u>4</u><u>m</u><u>m</u><u>²</u>

2.

for triangle

base[b]=6ft

height(h)=9ft

for square

length[l]=9ft

Area of figure=area of square +area of triangle

  • =l²+½*b*h
  • =9²+½*6*9
  • =81+27
  • =108ft²
  • <u>Area</u><u>:</u><u> </u><u>1</u><u>0</u><u>8</u><u>f</u><u>t</u><u>²</u>
6 0
2 years ago
Pythagorean theorem , HELPPP
sladkih [1.3K]

Answer:

A=150

Step-by-step explanation:

1/2ab=A

1/2 15x20 = 1/2 300 = 150 = A

Hope this Helps! :)

6 0
3 years ago
Read 2 more answers
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