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LekaFEV [45]
3 years ago
11

Please find the square roots of the following complex number.

Mathematics
1 answer:
Nana76 [90]3 years ago
6 0

Hey there,

First, find the square root of the given equation.

\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})

Best of Luck!

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-x - 163 = 12x + 84
Inessa05 [86]

Answer:

X = -19

Step-by-step explanation:

Add x to both sides to get rid of -x

-163 = 13x + 84

subtract 84 from both sides

-247 = 13x

divide by 13

x = -19

6 0
3 years ago
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1. Use the sequence to answer the questions. 2.5, 6, 9.5, 13, 16.5, 20,… (a) What is the common difference? (b) What is the recu
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