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TiliK225 [7]
3 years ago
12

Audrey is trying to find the equation of a line parallel to y = 2 over 3x _5 in slope-intercept form that passes through the poi

nt (_6, _1). Which of the following equations will she use?
y − (−6) = 2 over 3(x − (−1))

y − (−1) = 2 over 3(x − (−6))

y − (−6) = 3 over 2(x − (−1))

y − (−1) = 3 over 2(x − (−6))
Mathematics
2 answers:
KiRa [710]3 years ago
4 0
A line parallel to y = 2/3 x - 5 will have a slope of 2/3.
The equation of a line passing through (-6, -1) with a slope of 2/3 is
y - (-1) = 2/3 (x - (-6))


lidiya [134]3 years ago
3 0

Answer:  The correct option is

(B) y-(-1)=\dfrac{2}{3}(x-(-6)).

Step-by-step explanation:  Given that Audrey is trying to find the equation of a line parallel to y=\dfrac{2}{3}x-5 in slope-intercept form that passes through the point (-6, -1).

We are to find the equation of the line that she use.

The given line is

y=\dfrac{2}{3}x-5~~~~~~~~~~~~~~~~~~~~~~~(i)

Comparing the above equation with the slope-intercept form y=mx+c,, we have

\textup{slope, m}=\dfrac{2}{3}.

We know that the slopes of two parallel lines are equal.

So, the slope of the new line will also be

m=\dfrac{2}{3}.

Since the line passes through the point (-6, -1), so its equation will be

y-(-1)=m(x-(-6))\\\\\\\Rightarrow y-(-1)=\dfrac{2}{3}(x-(-6)).

Thus, the required equation of the line is

y-(-1)=\dfrac{2}{3}(x-(-6)).

Option (B) is CORRECT.

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3 years ago
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3 years ago
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What is the equation of the following graph in vertex form? PLEASE HELP ME!
viktelen [127]

Answer: Choice B

y = (x+3)^2 - 1

==================================================

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