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3 years ago

What is the distance between points A and B? Enter your answer, rounded to the nearest tenth, in the box. units

Mathematics

1 answer:

kupik [55]3 years ago

3 0

Answer:

Distance between A and B = 10.4 unit (Approx.)

Step-by-step explanation:

Given:

Coordinate of A = (-5 , 2)

Coordinate of B = (5 , 5)

Find:

Distance between A and B

Computation:

Using distance formula

Distance between two point = √(x1 - x2)² - (y1 - y2)²

Distance between A and B = √(-5 - 5)² - (2 - 5)²

Distance between A and B = √(-10)² - (-3)²

Distance between A and B = √100 + 9

Distance between A and B = √109

Distance between A and B = 10.4403

Distance between A and B = 10.4 unit (Approx.)

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3 years ago

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Vinvika [58]

Answer:

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And we can find this probability with the complement rule:

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And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

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