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djverab [1.8K]
3 years ago
9

Find the value of k. the diagram is not to scale

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0
Given:
<span>∠SRT ≅ ∠STR, 
m∠SRT = 20, 
m∠STU = 4x

Since </span>∠SRT ≅ ∠STR,  then m∠STR = 20.

m∠STR + m∠STU = 180°
20 + 4x = 180
4x = 180 - 20
4x = 160
4x/4 = 160/4
x = 40

The value of x is 40.



I hope this is what you're looking for.
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In a class 32 students, 4students we're homesick with the flu on Thursday. what percentage of the students were absent on Thursd
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Answer:

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Step-by-step explanation:

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THERE ARE 3 BAGS OF APPLES WEIGHING A TOTAL OF 22 1/2 POUNDS. TWO OF THE BAGS WEIGH 6 3/8 POUNDS AND 3 1/4 POUNDS. HOW MUCH DOES
Mkey [24]
I wasn't going to click on this one, but the all-caps enthralled me and hypnotized me.

first off, let's change all the mixed fractions to "improper" and proceed from there, keep in mind that if we subtract the two bags' weight from the total, what's leftover is the 3rd bag's weight.

\bf \stackrel{mixed}{22\frac{1}{2}}\implies \cfrac{22\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{45}{2}}&#10;\\\\\\&#10;\stackrel{mixed}{6\frac{3}{8}}\implies \cfrac{6\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{51}{8}}&#10;\\\\\\&#10;\stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}\\\\&#10;-------------------------------\\\\

\bf \stackrel{\textit{sum of the two bags}}{\cfrac{51}{8}+\cfrac{13}{4}}\impliedby \textit{our LCD is 8}\implies \cfrac{(1)51+(2)13}{8}&#10;\\\\\\&#10;\cfrac{51+26}{8}\implies \cfrac{77}{8}\\\\&#10;-------------------------------\\\\&#10;\stackrel{total}{\cfrac{45}{2}}~-~\stackrel{two~bags}{\cfrac{77}{8}}\impliedby \textit{our LCD is again 8}\implies \cfrac{(4)45-(1)77}{8}&#10;\\\\\\&#10;\cfrac{180~~-~~77}{8}\implies \cfrac{103}{8}\implies \stackrel{third~bag}{12\frac{7}{8}}
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mafiozo [28]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
How to solve it in quadratic functions
natita [175]

Answer:

x = 2

x = -3/2 or -1.5

Step-by-step explanation:

For this, I would use the "slip and slide" method. LOL I know the name is cheesy, but that's what my teacher called it!

First, you "slip" the coefficent of the leading term (2) to the constant, and multiply.

The equation becomes:

x² - x - 6(2) = 0

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Then, you factor this out by looking at the second and third terms. You're looking for 2 factors of -12 that would add up to -1 ( the coefficent of the second term).

Automatically, think of 3 and 4, because the difference between them is 1.

The factors must be (x-4) and (x+3) because they multiple to -12, and add up to -1.

This step is extremely important! Lol I used to forget it a lot, but make sure you divide the constant in each factor by the original number you "slipped".

It would become (x-(4/2))(x+3/2) = (x-2)(x+3/2)

With (x+3/2), you don't want to leave it as a fraction or decimal. It's equivalent to (2x+3). However, the informal form is easier to identify the value of x.

6 0
3 years ago
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