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andrew11 [14]
4 years ago
6

A youth group and their leaders visited mammoth cave. Two adults and 5 students in one van paid $77 for the grand avenue tour of

the cave. Two adults and 7 students in one sencond van paid $95 for the same tour.
Mathematics
1 answer:
il63 [147K]4 years ago
6 0

Answer:

Step-by-step explanation:

Notice that there are two adults in each equation. That means the difference in the price each group paid is because of the difference in the number of students! So you can actually just find the difference between the two equations and solve for s, and you will be headed in the right direction!

 

Equation 2 - Equation 1: 0a + 2s = $18

s = $9

 

Now substitute s into either equation, and you'll find the adult price:

2a + 5(9) = 77

2a + 45 = 77

2a = 32

a = $16

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6:1

Step-by-step explanation:

1 hr= 60 minutes

60 minutes= 3600 seconds

3600:600

36:6

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4 years ago
(50Pts) When using the vertical method to multiply polynomials, your like terms must be lined up in ____________.
lisov135 [29]

Answer:

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Step-by-step explanation:

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3 years ago
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Find the quadratic function that passes through the points: (-1,6), (1,4), and (2,9).
Masja [62]

Answer:

The quadratic function that passes through given points is                           y = 2 x² - x + 3  .

Step-by-step explanation:

The given quadratic function as

y = a x² + b x + c

The equation passes through the points ( - 1 , 6 ) , ( 1 , 4 ) and ( 2, 9 )

As The points passes through equation then

At points  ( - 1 , 6 )

6 = a (1)² + b ×( - 1 ) + c

Or, a - b + c = 6           .....A

Again At points  ( 1 , 4 )

4 = a (1)² + b × 1 + c

Or, a + b + c = 4            .......B

<u>Similarly At points  ( 2 , 9 )</u>

9 = a (2)² + b × 2 + c

Or, 4 a +2 b + c = 9        ....,,,C

<u>Now solving equation A and B</u>

(  a - b + c ) + (  a + b + c ) = 6 + 4

Or, a + c = \frac{10}{2}  

I.e a + c = 5           ......D

<u>Similarly Solving equation B and C</u>

( 4 a +2 b + c  ) - 2 × ( a + b + c ) = 9 - 2 × 4

Or, ( 4 a - 2 a + 2 b - 2 b + c - 2 c ) = 9 - 8

Or, ( 2 a - c ) = 1        .....E

<u>Solving D and E</u>

( a + c ) + ( 2 a - c ) = 5 + 1

Or, 3 a = 6

∴  a = \frac{6}{3}

I.e a = 2

<u>Put the value of a in Eq D</u>

So ,  a + c = 5

Or,  c = 5 - a

∴  c = 5 - 2 = 3

I.e  c = 3

<u>Put The value of a and c in Eq A</u>

a - b + c = 6      

Or, b = a + c - 6

Or . b = 2 + 3 - 6

∴ , b = 5 - 6

I.e   b = - 1

Now, <u>Putting the values of a , b , c in the given quadratic equation</u>

I.e y = a x² + b x + c

Or, y = 2 x² + ( - 1 ) x + 3

∴ The quadratic eq is  y = 2 x² - x + 3

Hence The quadratic function that passes through given points is                 y = 2 x² - x + 3  . Answer

8 0
3 years ago
4. What are the last TWO DIGITS of 2^2017
goldfiish [28.3K]

Compute 2²⁰¹⁷ modulo 100.

From the given table,

2²² ≡ 2⁴² ≡ 2⁶² ≡ 4 (mod 100)

and we have

2017 = 32 • 62 + 33

62 = 1 • 42 + 20

Then

2²⁰¹⁷ ≡ (2⁶²)³² • 2³³ (mod 100)

2²⁰¹⁷ ≡ 4³² • 2³³ (mod 100)

2²⁰¹⁷ ≡ (2²)³² • 2³³ (mod 100)

2²⁰¹⁷ ≡ 2⁶⁴ • 2³³ (mod 100)

2²⁰¹⁷ ≡ 2⁶² • 2²² • 2¹³ (mod 100)

2²⁰¹⁷ ≡ 4² • 2¹³ (mod 100)

2²⁰¹⁷ ≡ (2²)² • 2¹³ (mod 100)

2²⁰¹⁷ ≡ 2⁴ • 2¹³ (mod 100)

2²⁰¹⁷ ≡ 2¹⁷ (mod 100)

and from the table, we get

2²⁰¹⁷ ≡ 2¹⁷ ≡ 72 (mod 100)

8 0
3 years ago
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