Answer:
35 different routes
Step-by-step explanation:
The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.
Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.
The number of combinations of n objects taken r at a time is: ⁿCᵣ
So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by
⁷C₄ = 35 different ways.
Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.
Hope this Helps!!!
Answer:
what's the question? I don't know
The isosceles triangle is missing so i have attached it.
Answer:
Length of unknown side = 5p + 6
Step-by-step explanation:
In isosceles triangle, two of the sides are equal. In the attached triangle, we see that one of the equal sides is given as 5p + 3.
Thus,the second equal side is also 5p + 3.
Now, perimeter of a triangle is the sum of the three sides.
We have two sides and let the third side be denoted as x.
Thus;
Perimeter = (5p + 3) + (5p + 3) + x
We are given perimeter = 15p + 12
Thus;
(5p + 3) + (5p + 3) + x = 15p + 12
10p + 6 + x = 15p + 12
Rearranging, we have;
x = 15p - 10p + 12 - 6
x = 5p + 6
Answer:
Option 4
Step-by-step explanation:
y = -5x + 2
-8 = -5(2) + 2
-8 = -10 + 2
Correct! :)
The required range of the data is 24mm
The range of data is the difference between the largest value and the least value in a set of data.
Since we are not given the range of data. Let's assume we gave the following data:
34mm, 30mm, 20mm, 44mm, 31mm
From the data
Highest measurement = 44mm
Least measurement = 20mm
Find the range
Range = Highest measurement - Least measurement
Range = 44mm - 20mm
Range = 24mm
Hence the required range of data is 24mm
<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>
<em>Learn more here: brainly.com/question/1786006</em>
