1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kvasek [131]
3 years ago
8

Jack is 20 miles due north of Edward. Sarah is due east of Edward. The angle between the direction of the shortest distance from

Sarah to Jack and due east is 25°. To the nearest mile, how far is Sarah from each man?

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

The distance between Sarah and Jack is approximately 22 miles

The distance between Sarah and Jack is approximately 9 miles

Step-by-step explanation:

The explanation in the attached file

You might be interested in
Find the value of z please help
Elza [17]

z + 93 = 180

z = 87

Answer z = 87

Here are the answer for x and y, in case you need them.

x = 2* 93 - 112

x = 186 - 112

x = 74

y = 2 * 80 - x

y = 160 - 74

y = 86

6 0
3 years ago
Read 2 more answers
Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following
posledela

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{165.9}{6} = 27.65

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%

5 0
2 years ago
ABCD is a rectangle. Rectangle A B C D is shown. All angles are right angles. The length of A D is 5 and the length of D C is 12
sashaice [31]

Answer: 13

Step-by-step explanation:

I used Pythagorean theorem to solve this problem. As DC and AD is 12 and 5, you would do 12²+5²= c². 12²= 144 and 5²= 25. 144+25= 169. It doesn't end there. Do the square root of 169 ---> √169=13.

3 0
3 years ago
If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,
julsineya [31]
<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

<h2>Why?</h2>

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)

(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0
3 years ago
What types of problems can be solved using the greatest common factor what type of problems can be solved using the least common
Tanzania [10]
There could be problems like there is a light which would flicker in every 7 seconds and there is another one which would flicker in every 8 seconds. So, how many times would they flicker until they would flicker at the same time? 
6 0
3 years ago
Other questions:
  • 10^-x=3^2x what is the answer
    7·1 answer
  • If the probability of being a great ape is 0.01 and the probability of having orange hair is 0.2, and having orange hair and bei
    11·1 answer
  • Help asap show work
    10·1 answer
  • Without using a calculator, what is 30% of 546? (You can round up to avoid decimal points)
    12·2 answers
  • Please help me with this problem.​
    5·1 answer
  • Choose the most convenient method to graph the line 2x+5y=−10.
    7·1 answer
  • How do I find question number 43
    6·1 answer
  • Show your work on how you got the answer<br><br> please helppp
    9·1 answer
  • F(x) = 2x + 5
    10·1 answer
  • PLEASE HELP ME OVER HERE
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!