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tangare [24]
3 years ago
14

Pat created a scatter plot and drew a line of best fit, as shown.

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0
<h3>Answer:  Choice D</h3><h3>y = (-1/5)x + 7</h3>

======================================

Work Shown:

We will only focus on the two points that are on the regression line.

Those two points are (10,5) and (15,4)

Let (x1,y1) = (10,5) and (x2,y2) = (15,4)

Find the slope of the line through (x1,y1) = (10,5) and (x2,y2) = (15,4)

m = (y2 - y1)/(x2 - x1)

m = (4 - 5)/(15 - 10)

m = -1/5

m = -0.2

Plug m = -0.2, and  (x1,y1) = (10,5) into the point slope formula. Solve for y

y - y1 = m(x - x1)

y - 5 = -0.2(x - 10)

y - 5 = -0.2*x - 0.2*(-10) ... distribute

y - 5 = -0.2*x + 2

y - 5+5 = -0.2*x + 2 + 5 ... add 5 to both sides

y = -0.2*x + 7

y = (-1/5)*x + 7 .... convert -0.2 to -1/5

The equation y = (-1/5)x + 7 is in the form y = mx+b with m = -1/5 = -0.2 as the slope and b = 7 as the y intercept. The y intercept is where the graph crosses the vertical y axis. More specifically, the location of the y intercept in this case is at the point (0,7).

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nydimaria [60]

Answer:

f(5.5)≈27.32

Step-by-step explanation:

5 0
3 years ago
What is 50 divide by 25 times 2 divided by 5 ?
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0.8 i think I’m not sure .
3 0
3 years ago
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PLEASE HELP ME FINISH! Algebra 1b unit 7 lesson 2.
IceJOKER [234]
1.  50*2^18
2.DACB
3.graph will have value 30 at x=0 and it will be increasing exponentially.
4 0
3 years ago
Which of the following statements uses the additive identity? 9 + 0 = 9 9 · 0 = 0 9 + 1 = 1 + 9 (9)(1) = (1)(9)
m_a_m_a [10]
<h3>Answer: 9+0 = 9</h3>

The additive identity is 0. If you add 0 to any number, then you get the same number as a result. In general, x+0 = x where x is a place holder for any number. For this problem, x = 9 so that's how 9+0 = 9.

4 0
3 years ago
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The average monthly cell phone bill was reported to be $50.07 by the U.S. Wireless Industry. Random Sampling of a large cell pho
zalisa [80]

Answer:

The null and alternative hypotheses are:

H_{0}:\mu= 50.07

H_{a}:\mu>50.07

Under the null hypothesis, the test statistic is:

t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }

Where:

\bar{x} = 52.86 is the sample mean

s=7.0132 is the sample standard deviation

n=10 is the sample size

\therefore t=\frac{52.86-50.07}{\frac{7.0132}{\sqrt{10}} }    

          =1.26

Now, the right tailed t critical value at 0.05 significance level for df = n-1 = 10-1 = 9 is:

t_{critical}=1.833

Since the t statistic is less than the t critical value at 0.05 significance level, therefore,we fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the average phone bill has increased.


4 0
3 years ago
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