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Ede4ka [16]
3 years ago
11

Where should an object be placed in front of a concave mirror’s principal axis to form an image that is real, inverted, larger t

han the object, and farther from the mirror than the object is?
a. at the focal point on the principal axis
b. at the center of curvature on the principal axis
c. between the center of curvature and focal point on the principal axis
d. between the focal point and the vertex on the principal axis
Physics
2 answers:
malfutka [58]3 years ago
8 0
<em> I believe the answer is letter C.</em>
mart [117]3 years ago
4 0

Answer:

option C

Explanation:

In a concave mirror for the image to be real, inverted  and enlarged the object must be place between the center of curvature and focal point on the principal axis. To obtain an enlarged image object must not in proximity of the mirror, it should be far. The image formed will be on the same side as object( real ). but image will be inverted.

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A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5
harkovskaia [24]

Answer:

The kinetic energy is: 50[J]

Explanation:

The ball is having a potential energy of 100 [J], therefore

PE = [J]

The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\

This energy is equal to the kinetic energy, therefore

Ke= 50 [J]

8 0
3 years ago
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Answer:

Both the astronauts and photographer have the same displacement

Explanation:

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Hence, both the astronauts and photographer will have the same displacement.

3 0
4 years ago
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nonrenewable: rocks, soil

i hope this helps :)

5 0
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The emf will be induced in anti-clockwise direction.

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