1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
10

Fr-ee p-o-i-n-t-s is biden bad yes or no and tell me why

Physics
2 answers:
dalvyx [7]3 years ago
5 0

Answer:

Wohhh thanks for you free answer. Well i will be appreciating it.

iragen [17]3 years ago
5 0

Answer:

Not sure

Explanation:

Im not really into politics but what ive heard so far hes in-between both good and bad

You might be interested in
Help with i) and ii) pls >_
alina1380 [7]

Answer:

4 it the corrcert anser

Explanation:

4 0
3 years ago
Read 2 more answers
Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where l
goblinko [34]

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

\Delta t = \frac{0.18\ m}{340\ m/s}

<u>Δt = 5.29 x 10⁻⁴ s = 0.529 ms</u>

4 0
3 years ago
¿cual es la velocidad de un auto que recorre 4566 metros en 4 minutos? expresar en km\h
Svetlanka [38]

Explanation:

(4566 m / 4 min) × (1 km / 1000 m) × (60 min / h) = 68.49 km/h

3 0
3 years ago
Two planets have masses 2 x 10^23 kg and 5 x 10^22 kg, and the distance between them is 3 x 10^16 m. Calculate the gravitational
xxTIMURxx [149]

Explanation:

given,

mass of one planet (m1)=2*10^23 kg

mass of another planet (m2)=5*10^22kg

distance between them(d)=3*10^16m

gravitational constant(G)=6.67*10^-11Nm^2kg^-2

gravitational force between them(F)=?

we know,

F=Gm1m2/d^2

or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2

or, F=6.67*2*5*10^-11+23+22/3*3*10^32

or, F=66.7*10^34/9*10^32

or, F=7.41*10^34-32

•°• F=7.41*10^2

thus, the gravitational force between them is 7.14*10^2

3 0
3 years ago
The current in a hair dryer measures 15 amps. The resistance of the hair dryer is 14 ohms. What is the voltage?
ZanzabumX [31]
We have that there is a formula connecting these three. V=I*R where V is voltage, I is the current and R is the resistance. Substituting, we get that V=210 Volta, which is the unit of measurement for voltage. You can think of the relationship in the following way : The energy of the field is equal to the flow of the field times the resistance that it meets.
6 0
3 years ago
Other questions:
  • The universal force that is effective over the longest distance between very massive objects like planets is
    7·1 answer
  • How do magnetic forces repel or attract?<br> Plz make it as simple as possible
    9·1 answer
  • How many minutes does light need to travel from the sun to Jupiter?
    15·1 answer
  • A scientist adds different amounts of salt to 5 bottles of water. He then measures how long it takes for the water to boil. what
    14·1 answer
  • What best describes the angle between a changing electric field and the electromagnetic wave produced by it?
    12·1 answer
  • In 1985, Said Aouita set the world record for the 1500m race in a time of 3 minute 29.46 second ? What was his average speed ?
    14·1 answer
  • Which equation represents the total energy of a system
    6·1 answer
  • How many hydrogen atoms are in water, H2O?
    11·1 answer
  • Can some one help with this question? "What is the relationships between. The force due to friction and the force due to gravity
    10·1 answer
  • the autor mentions that shine made several mistakes in her experiment. describe one Major mistake that shine made. support your
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!