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s2008m [1.1K]
3 years ago
10

Fr-ee p-o-i-n-t-s is biden bad yes or no and tell me why

Physics
2 answers:
dalvyx [7]3 years ago
5 0

Answer:

Wohhh thanks for you free answer. Well i will be appreciating it.

iragen [17]3 years ago
5 0

Answer:

Not sure

Explanation:

Im not really into politics but what ive heard so far hes in-between both good and bad

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What is the acceleration of an object with mass of 42.6 kg when an unbalanced force of 112 N is applied to it
lord [1]
The answer is 2.63m/s^2! You use the formula F=ma, 112 = 42.6(a), a= 2.63m/s^2.
7 0
3 years ago
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BERE
Kisachek [45]

Answer:

All points to the left of zero are negative

Explanation:

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2 years ago
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A team of bicyclists are on bikes that require 512 J of work to ride. It takes 432 J of work for the bike to turn the gears. Wha
Alja [10]

Answer:

84.4 %

Explanation:

Mechanical efficiency = output work/input work × 100 %

output work = 432 J of work for the bike to turn the gears

input work = 512 J of work to ride.

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= 0.844 × 100%

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3 years ago
What planet is closet in mass to earth
alexdok [17]

Answer:venus

Explanation:

is most like Earth in terms of mass and size, and it is also the planet closest to Earth, but the two planets are far from identical twins.

3 0
3 years ago
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An upright object 2.80 cm tall is placed 16.0 cm away from the vertex of a concave mirror with a center of curvature of 24.0 cm.
horrorfan [7]

Answer:

f = 12 cm

Explanation:

<u>Center of Curvature</u>:

The center of that hollow sphere, whose part is the spherical mirror, is known as the ‘Center of Curvature’ of  mirror.

<u>The Radius of Curvature</u>:

The radius of that hollow sphere, whose part is the spherical mirror, is known as the ‘Radius of Curvature’ of  mirror. It is the distance from pole to the center of curvature.

<u>Focal Length</u>:

The distance between principal focus and pole is called ‘Focal Length’. It is denoted by ‘F’.

The focal length of the spherical (concave) mirror is approximately equal to half of the radius of curvature:

f = \frac{R}{2}

where,

f = focal length = ?

R = Radius of curvature = 24 cm

Therefore,

f = \frac{24\ cm}{2}

<u>f = 12 cm</u>

8 0
3 years ago
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